The absolute value of a negative integer
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Answer: The point where the two graphed lines cross is the solution to the system of equations. (1, -1)
Step-by-step explanation:
The second equation is already in slope-intercept form y = x - 2
the slope is +1 (invisible coefficient of x) and the y-intercept is -2
y = mx +b
"m" is the slope (the coefficient of x) Positive slopes go up from left to right
"b" is the y-intercept, where the graphed line crosses the x-axis
Rewrite the first equation in slope-intercept form.
6x + y = 5 subtract 6x from both sides
<em>-6x</em> + 6x +y = -<em>6x</em> + 5 .( left side 6x + 6x =0 so "cancel")
y = -6x + 5
Then you know the slope and the intercepts
b = 5 so start with a point at +5 in the y-axis
m = -6 so from there go down 6 and over to the right 1 square and plot another point. Draw a straight line through the two points.
The point where the two graphed lines cross is the solution to the system of equations.
Your graph should look like the screenshot below.
