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3 years ago

Quadrilateral QRST is a square. If the measure of RS is 12x + 5 and QT is 8x + 15. find the value of QR

Mathematics

2 answers:

dybincka [34]3 years ago

8 0

Answer:

Step-by-step explanation:

valentina_108 [34]3 years ago

7 0

Answer:

Step-by-step explanation:

I got you the answer is 35.

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Can anyone help me integrate :

worty [1.4K]

Rewrite the second factor in the numerator as

$2x^2+6x+1=2(x+2)^2-2(x+2)-3$

Then in the entire integrand, set $x+2=\sqrt3\sec t$ , so that $\mathrm dx=\sqrt3\sec t\tan t\,\mathrm dt$ . The integral is then equivalent to

$\displaystyle\int\frac{(\sqrt3\sec t-2)(6\sec^2t-2\sqrt3\sec t-3)}{\sqrt{(\sqrt3\sec t)^2-3}}(\sqrt3\sec t)\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\sec^2t-1}}\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\tan^2t}}\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{|\tan t|}\,\mathrm dt$

Note that by letting $x+2=\sqrt3\sec t$ , we are enforcing an invertible substitution which would make it so that $t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}$ requires $0\le t$ or $\dfrac\pi2$ . However, $\tan t$ is positive over this first interval and negative over the second, so we can't ignore the absolute value.

So let's just assume the integral is being taken over a domain on which $\tan t>0$ so that $|\tan t|=\tan t$ . This allows us to write

$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\tan t}\,\mathrm dt$
$=\displaystyle\int(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\csc t\,\mathrm dt$

We can show pretty easily that

$\displaystyle\int\csc t\,\mathrm dt=-\ln|\csc t+\cot t|+C$
$\displaystyle\int\sec t\csc t\,\mathrm dt=-\ln|\csc2t+\cot2t|+C$
$\displaystyle\int\sec^2t\csc t\,\mathrm dt=\sec t-\ln|\csc t+\cot t|+C$
$\displaystyle\int\sec^3t\csc t\,\mathrm dt=\frac12\sec^2t+\ln|\tan t|+C$

which means the integral above becomes

$=3\sqrt3\sec^2t+6\sqrt3\ln|\tan t|-18\sec t+18\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|-6\ln|\csc t+\cot t|+C$
$=3\sqrt3\sec^2t-18\sec t+6\sqrt3\ln|\tan t|+12\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|+C$

Back-substituting to get this in terms of $x$ is a bit of a nightmare, but you'll find that, since $t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}$ , we get

$\sec t=\dfrac{x+2}{\sqrt3}$
$\sec^2t=\dfrac{(x+2)^2}3$
$\tan t=\sqrt{\dfrac{x^2+4x+1}3}$
$\cot t=\sqrt{\dfrac3{x^2+4x+1}}$
$\csc t=\dfrac{x+2}{\sqrt{x^2+4x+1}}$
$\csc2t=\dfrac{(x+2)^2}{2\sqrt3\sqrt{x^2+4x+1}}$

etc.

3 0

3 years ago

WRITE AN EQUATION THAT MODELS EACH STATEMENT :

enot [183]

Step-by-step explanation:

Take John's sister's age as "x"

So, so twice his sister's age means = 2x

And 5 years more, means = 2x + 5

So finally John's age = 2x + 5

5 0

3 years ago

Read 2 more answers

Xxx’s recipe from oatmeal muffins calls for 2 1/2 cups of oatmeal and makes one dozen muffins.

sasho [114]

Answer:18.75

Because if you combine each group of dozens you can then do 5x2.5 which equals 12.5 so then you do 1.5 of 2.5 and get 6.25

5 0

2 years ago

un automovil marcha durante 3/8 del dia a una velocidad constante de 16 km/h ¿cual es el espacio recorrido?.......Doy corona al

Tanzania [10]

Answer:

LOL

Step-by-step explanation:

144 KILOMETROS....

5 0

3 years ago

Raul simplified the expression, as shown below.

Softa [21]

Answer:

Raul's errors are in the application of the distributive property(he applied it wrongly), in not respecting the precedence of operations, and in the multiplication of two terms with the same base(we add the exponent).

Step-by-step explanation:

Distributive property:

The distributive property of multiplication is:

a*(b + c) = a*b + a*c

Precedence of operations:

First multiplication, then addition.

Multiplication of terms with the same base:

The multiplication of h*h = h², which Raul missed.

The correct simplification is given by:

$-[3h + 7h(2-h)] = -[3h + 14h - 7h^2] = -[17h - 7h^2]=7h^2 - 17h$

4 0

3 years ago

Read 2 more answers

Quadrilateral QRST is a square. If the measure of RS is 12x + 5 and QT is 8x + 15. find the value of QR ​

Quadrilateral QRST is a square. If the measure of RS is 12x + 5 and QT is 8x + 15. find the value of QR