The answer is 7/5
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Good luck on your assignment
D. 12
Pretty much the smallest number both denominators can go in.
So the multiples of
4: 4,8,12
3:3,6,9,12
Answer:
no solutions
Step-by-step explanation:
4 + 5m = 4m + 1 + m <em>combine like terms</em>
4 + 5m = 5m + 1 <em>subtract 5m from each side</em>
4 = 1
4 can never equal 1, so no value of m would allow the equation to be correct
Answer:
Kindly check explanation
Step-by-step explanation:
H0 : μ = 5500
H1 : μ > 5500
The test statistic assume normal distribution :
Test statistic :
(Xbar - μ) ÷ s/sqrt(n)
(5625.1 - 5500) ÷ 226.1/sqrt(15) = 2.1429 = 2.143
Pvalue from test statistic :
The Pvalue obtained using the calculator at df = 15 - 1 = 14 is 0.025083
α = 0.05
Since ;
Pvalue < α
0.025083 < 0.05 ; Reject H0
The confidence interval :
Xbar ± Tcritical * s/sqrt(n)
Tcritical at 95% = 1.761 ;
margin of error = 1.761 * 226.1/sqrt(15) = 102.805
Lower boundary : (5625.1 - 102.805) = 5522.295
(5522.295 ; ∞)
The hypothesized mean does not occur within the constructed confidence boundary. HENCE, there is significant eveidbce to support the claim that the true mean life of a biomedical device is greater than 5500
Answer:
a: 162
b: 142
Step-by-step explanation:
a: december 1=2
a: december 2=6
a: december 3 = 6 x 3 = 18
a: december 4 = 18 x 3 =54
a: december 5 = 54 x 3 =162
~ triples the number of newspapers means "x3" ~
so on the last day, 162 newspapers
B: sum up all the newspapers:
2 + 6 + 18 + 54 + 162
= 8 + 18 + 54 + 162
= 26 + 54 + 162
= 80 + 162
= 242 all in total newspapers
