Determine the taxi distance from point C(2, 4) to point D(1, 7).

Mathematics

1 answer:

Readme [11.4K]3 years ago

6 0

The distance is 3.16 (label whatever is appropriate)

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How to write the number in 4different ways

mario62 [17]

Lets say the number is 155:

100 + 50 + 5

one hundred and fifty-five

155

idk the last one tho

there should be only 3 ways, plz double check

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3 years ago

An object is moving at a speed of 2 feet every 8.5 minutes. Express this speed in meters per hour

jekas [21]

Answer:

4.30m/hr

Step-by-step explanation:

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2 years ago

It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi

Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that $\mu = 35000, \sigma = 7000$

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

$Z = \frac{X - \mu}{\sigma}$

$-1.88 = \frac{X - 35000}{7000}$