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3 years ago

Which of these are the x- and y-intercepts of the graph?

Mathematics

1 answer:

Blizzard [7]3 years ago

7 0

Your answer will be B. Your x value is on -6 and y would be 0 at that point, making it (-6,0). Your y intercept is on the 3 and x is 0, making it (0,3).

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NEED HELP AND NEED TO SHOW WORK

Olin [163]

Answer:

f(-2) = 0

f(1) = 12

(x^3 - 7x - 6) / (x + 2) = x^2 - 2·x - 3 = (x - 3)(x + 1)

x^3 - 7x - 6 = (x + 2)(x - 3)(x + 1)

7 0

3 years ago

AB and BC form a right angle at point B if A = (-3,-1) and B = (4,4) what is the equation if BC

sergejj [24]

Answer:

$7x+5y-48=0$

Step-by-step explanation:

Refer the attached figure .

We are given a line AB

Point A $=(x_1,y_1) = (-3,-1)$

Point B $=(x_2,y_2) = (4,4)$

Formula for slope 'm' when two points are given :

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting thew values

$m=\frac{4-(-1)}{4-(-3)}$

$m=\frac{5}{7}$

Since we are given that AB is perpendicular to BC

So, By property - perpendicular slopes are negative reciprocals of each other.

$\Rightarrow m_1\times m_2 =-1$

$\Rightarrow \frac{5}{7}\times m_2 =-1$

$\Rightarrow m_2 = \frac{-7}{5}$

So, Slope for line BC : $m_2 = \frac{-7}{5}$

Point B = (4,4)

Formula of equation of line : $y-y_1=m(x-x_1)$

$y-4=\frac{-7}{5}(x-4)$

$5(y-4)=-7(x-4)$

$5y-20=-7x+28$

$7x+5y-20-28=0$

$7x+5y-48=0$

Hence the equation of line BC : $7x+5y-48=0$

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Answer:

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Karo-lina-s [1.5K]

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