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n200080 [17]
3 years ago
6

Estimate the quotient 719.711 divied by 8.75

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
3 0
We can round 719.711 to 720 and 8.75 to 9
720/9 = 80
So the estimate would be 80
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HELPPP!!! can someone turn 3x−2=13 into a WORD problem. (i already know answer)
postnew [5]
Answer:
2 less than 3 times a number is 13
5 0
2 years ago
1400 dollars is placed in an account with an annual interest rate of 7.75%.To the nearest tenth of a year, how long will it take
mestny [16]

Answer:

46 years 1 month

Step-by-step explanation:

Let us assume the investment is a simple interest investment

The simple interest formula is

A= P(1+rt)

Given

Principal p= $1400

Rate r= 7.75%= 7. 75/100= 0.0775

Final amount A = $6400

Time t=?

To find the time t let us substitute our values in the simple interest formula

6400= 1400(1+0.0775t)

6400= 1400+108.5t

6400-1400=108.5t

5000= 108.5t

t=5000/108.5= 46.08

t= 46.1 years

It will take approximately 46 years 1 month to get the amount

6 0
3 years ago
Read 2 more answers
7
Liono4ka [1.6K]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Pls i need help with this
schepotkina [342]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
At a large bank, account balances are normally distributed with a mean of $1,637.52 and a standard deviation of $623.16. What is
svp [43]

Answer:

P(\bar X >1650)=P(Z>\frac{1650-1637.52}{\frac{623.16}{\sqrt{400}}}=0.401)

And we can use the complement rule and we got:

P(Z>0.401) =1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the bank account balances of a population, and for this case we know the distribution for X is given by:

X \sim N(1637.52,623.16)  

Where \mu=1637.52 and \sigma=623.16

Since the distribution of X is normal then the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got:

P(\bar X >1650)=P(Z>\frac{1650-1637.52}{\frac{623.16}{\sqrt{400}}}=0.401)

And we can use the complement rule and we got:

P(Z>0.401) =1-P(Z

5 0
3 years ago
Read 2 more answers
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