Please I need help Please!!<br> Solve for x

Claire eats two pieces of buttered toast and a glass of pineapple juice for breakfast every day.

Bingel [31]

Answer:

B and C

Step-by-step explanation:

Since the price of one slice is B then 2 pieces has the price of 2B amd the total cost equals 2B+J

then to calculate the total cost for 7 days you have to multiply the cost for one day by 7 which is 7(J+2B) or if you expand that phrase you get 7J+14B

5 0

3 years ago

Read 2 more answers

Alison has $1.60 worth of nickels and dimes in her coin purse. She has 11 more nickels than dimes.

zimovet [89]

32 nickles and 42 dimes

8 0

4 years ago

PLEASE HELP WITH THIS

Kitty [74]

I think it is B -2 < x < 2

4 0

3 years ago

the other three finish painting the kitchen.write an equation to represent a way the four grandchildren.could have shared the pa

olga_2 [115]

Answer:

Step-by-step explanation:

The fraction 8/8 is an improper fraction. A proper fraction is one in which the numerator is less than the denominator.

1/1, 2/2, 3/3, 4/4, 5/5, 6/6, 7/7, 8/8, 9/9, 10/10, 11/11, 12/12, 13/13, 14/14, 15/15 ...

6 0

3 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

4 years ago

Please I need help Please!! Solve for x