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4 years ago

18 hours[60 seconds/ 1 minute]=1080 seconds

1 answer:

8 0

1 hour = 60 minutes
1 minute = 60 seconds

60 minutes x 60 seconds = 3600 seconds per hour

18 hours x 3600 seconds per hour = 64,800 seconds

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Determine the domain and range of the following function. Record your answers in set notation. The domain is {x∈R| x≠−5}, and th

Law Incorporation [45]

Answer:

Option (2)

Step-by-step explanation:

Domain of a function is represented by the set of x-values (Input values) and Range of the function is represented by the set of y-values (Output values)

From the graph attached,

Given function is,

$f(x)=\frac{x^2-x-6}{x+2}$

Domain of this function will be {x ∈ R | x ≠ -2}

[Since, point x = -2 doesn't lie on the given graph]

Range of the function will be {y ∈ R | y ≠ -5}

Therefore, Option (2) will be the correct option.

3 0

3 years ago

1 2 3 4 5 6 7 8 9 10 TIME REMAINING 01:47:21 Which best describes the relationship between the successive terms in the sequence

ehidna [41]

Answer: ARITHMETIC PROGRESSION

Step-by-step explanation:

An arithmetic progression where the indices are defines as

FIRST TERM ; 1

COMMON DIFFERENCE ; 1

NUMBER OF TERMS ;1

LAST TERM ; 10

SUM OF TERMS ; 55

3 0

3 years ago

Decide if the statement about the graphs that you completed are true or false:

Rina8888 [55]

Answer:

Step-by-step explanation:

6 0

3 years ago

Which values represent the first two terms of the sequence a1=2 and an=-2(an-1)^2?

Mars2501 [29]

Hello,

$a_{1}=2$
$a_{n+1}=-2*a_{n}^2$

$a_{1}=2$
$a_{2}=-2*2^{2}=-8$
$a_{3}=-2*(-8)^{2}=-2*64=-128$

Answer C

3 0

3 years ago

Suppose that a random variable X is continuously uniform between the values of 3 and 8. Find the variance of the distribution of

Korolek [52]

The formula of the variance of the distribution of sample mean of a random variable X, which it will denoted by $V(\bar{X}),$ is

$\frac{\sigma^2_X}{n}\ ,\\$

where n is the size of the sample.

Since X is continuously uniform between 3 and 8, you have

$\sigma^2_X = \frac{(8-3)^2}{12} = \frac{25}{12} \ .$

Therefore, the variance wanted is $V(\bar{X} ) = \frac{25}{26\cdot12}\approx0.0801$

5 0

3 years ago