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3 years ago

Which values represent the first two terms of the sequence a1=2 and an=-2(an-1)^2?

Mathematics

1 answer:

Mars2501 [29]3 years ago

3 0

Hello,

$a_{1}=2$
$a_{n+1}=-2*a_{n}^2$

$a_{1}=2$
$a_{2}=-2*2^{2}=-8$
$a_{3}=-2*(-8)^{2}=-2*64=-128$

Answer C

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$\displaystyle \: {h}^{2} + (\frac{l}{2} {)}^{2} = {s}^{2}$

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cancel 16 from both sides:

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square root both sides:

$\displaystyle \: \therefore \: {h}^{} = 3$

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$\displaystyle V_{pyramid}=\dfrac{1}{3}\times A\times h$

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$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times 64\times 3$

reduce fraction:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{ \cancel{ 3 \: }}\times 64\times \cancel{ \: 3}$

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Answer:

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