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2 years ago

Which values represent the first two terms of the sequence a1=2 and an=-2(an-1)^2?

Mathematics

1 answer:

Mars2501 [29]2 years ago

3 0

Hello,

$a_{1}=2$
$a_{n+1}=-2*a_{n}^2$

$a_{1}=2$
$a_{2}=-2*2^{2}=-8$
$a_{3}=-2*(-8)^{2}=-2*64=-128$

Answer C

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Pls Answer ..........

GuDViN [60]

Answer: The correct answer would be C

Step-by-step explanation: as the term number increases, the number of stars icreases by two. using this information, term ten would have 21 which is less than 30

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2 years ago

PLEASE HELP ME ASAP!! Write the following statement as an inequality: 8 less than a number w is under 35.

Lesechka [4]

Answer:

8<w<35

Step-by-step explanation:

the w has to be over 8, but less than 35, so 8<w<35 is ur answer.

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2 years ago

PLEASE HELP ME

irina1246 [14]

Answer:

B) $(-1, -2)$

Step-by-step explanation:

3x + 1 = x - 1

-3x - 3x

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1 = −2x - 1

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2 = −2x

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−2 −2

$x = -1$ [Plug this back into both equations above to get the y-coordinate of -2]; $-2 = y$

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6 0

3 years ago

A biologist is studying the growth of a particular species of algae. She writes the fall inclusion to show the radius of the alg

horrorfan [7]

Answer:

Part A)

A reasonable domain to plot the growth function is:

$0\leq d \leq 12$

Part B)

The y-intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from d = 4 to d = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after d days is given by the function:

$f(d)=5(1.02)^d$

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for d. Therefore:

$6.34=5(1.02)^d$

Divide both sides by five:

$(1.02)^d=1.268$

Take the log of both sides with base 1.02:

$\displaystyle d=\log_{1.02}1.268$

Using the Change of Base Property, evaluate for d:

$\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12$

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

$0\leq d\leq 12$

Part 2)

The y-intercept of the function is when d = 0. Find the y-intercept:

$f(0)=5(1.02)^{(0)}=5(1)=5$

Since d represent the amount of days after the study had begun, the y-intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from d = 4 to d = 11.

Find the endpoints:

$f(4)=5.4121...\text{ and } f(11)=6.2168...$

And find the slope between them:

$\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11$

Since f(d) measures millimeters and d measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

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2 years ago

A patient has been ordered Oxycodone 10mg Q6H PO for 5 days. How many 10mg tablets should be dispensed?

docker41 [41]

Answer:20 tablets

Step-by-step explanation:

Asked my MD father.

7 0

2 years ago

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