Answer:
Step-by-step explanation:
Given :
A bag contains 10 blue, 6 green, and 4 red marbles.
You choose one marble. Without putting it back, you choose a second marble.
To Find: What is the probability that you first choose a green marble and then a blue marble?
Solution:
No. of blue balls = 10
No. of green balls =6
No. of red marbles =4
Total no. of marbles = 10+6+4 =20
Since we are given that first he choose a green marble
So, probability of getting green marble :
=
Since he choose second marble without replacement
So, after choosing first ball . The total no. of balls will be 19
So, Probability of getting blue marble in second draw :
=
The probability that you first choose a green marble and then a blue marble:
Hence the probability that you first choose a green marble and then a blue marble is