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cricket20 [7]
2 years ago
11

The hydra was a one-headed monster but when iris cut off ,2 heads grow back in its place. If a hero tried to conquer it by cutti

ng off its head every day, how many heads would the hydra have on the third day? And at the end of 10 days of trying to it?
Mathematics
1 answer:
Cerrena [4.2K]2 years ago
4 0

Answer:

3 days: 8 heads.

10 days: 1024 heads.

Step-by-step explanation:

If each time the hero cuts off all the heads, then the amount doubles each time. This can also be represented using powers of 2, with 2^n, where n is the number of days.

2^1 = 2, so two heads the first time he cuts it.

2^2 = 4, so four heads the second time he cuts it.

With three, 2^3 is 8 so there are 8 heads.

With ten, 2^10 is 1024 so there are 1024 heads.

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On a cold February morning, the radiator fluid in Stanley’s car is -18 degrees When the engine is running, the temperature goes
Rasek [7]

Remark

This is an arithmetic progression. You have the first and last terms and the difference.

Givens

a = - 18

L = 60

d = 4.5        

Equation

L = a + (n - 1)d

Solve

60 = -18 + (n - 1) * 4.5   Add 18 to both side

60 + 18 = (n - 1) * 4.5      

78 = (n - 1) * 4.5           Divide both sides by 4.5

78/4.5 = n - 1

17.3333 = n - 1             Add 1 to both  sides.

18.3333 = n

Conclusion

It will that 18 1/3 or 18.33333 minutes to get the from -18 to 60 degrees.


3 0
2 years ago
G a survey of property owners' opinions about a street-widening project was taken to determine if owners' opinions were related
Naily [24]

Answer:

The expected frequency for people against the project and who have over 120 feet of property foot frontage is 3.9.

Step-by-step explanation:

The data provided is:

                                                   Opinion    

Front Footage   For       Undecided Against    Total

Under 45 feet    12                4              4              20

  45-120 feet           35                5             30      70

Over 120 feet     3                2              5              10

       Total           50                11             39    100

The formula to compute the expected frequency is:

E(X)=\frac{\text{Row Total}\times \text{Column Total}}{\text{TOTAL}}

Compute the expected frequency for people against the project and who have over 120 feet of property foot frontage as follows:

E(X)=\frac{\text{Row Total}\times \text{Column Total}}{\text{TOTAL}}

E(5)=\frac{10\times 39}{100}=\frac{39}{10}=3.9

Thus, the expected frequency for people against the project and who have over 120 feet of property foot frontage is 3.9.

6 0
2 years ago
Find angle GEH, which is located inside inscribed hexagon ABCDEF.
Zinaida [17]

Answer:

60°

Step-by-step explanation:

Angle GHE = (360/6) ÷ 2 = 30

GEH = 180 - 90 - 30 = 60°

7 0
3 years ago
How tall is the tree?<br> 5ft<br> 35°<br> -20ft-<br> [? ]ft
SVEN [57.7K]

Answer:

  • \boxed{\bf 19ft}

Step-by-step explanation:

\bf tan\:\theta =\cfrac{opp}{adj}

\bf tan(35^o)=\cfrac{x}{20}

\bf 20\;tan (35^o)=x

\bf 14ft=x

<u>The height of the tree:-</u>

  • \bf x+5ft
  • \bf 14ft+5ft
  • \bf 19ft
3 0
2 years ago
Read 2 more answers
The midpoint of EF is M(4,10) one endpoint is E(2,6). Find the coordinates of the other endpoint F
Vera_Pavlovna [14]
2+a / 2 = 4 and b+6 /2 = 10

2+a=8. and. b+6 = 20
a=6. and. b=14

(a,b) , the other endpoint, is thus (6,14)
3 0
3 years ago
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