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zmey [24]
4 years ago
12

How do I solve this? I am completely lost! Please help!

Mathematics
2 answers:
dedylja [7]4 years ago
5 0
Use the distributive rule
But the answer is X^2 + 4x + 3
Hope this helped :)
Airida [17]4 years ago
3 0
\frac{y(y-2)}{(y+5)(y+2)} × (y+5)
<span>The answer is:
</span>\frac{y(y-2)}{y+2}

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nadya68 [22]

Answer:

f(x) =x^2+6 is a quadratic function because is x^2, other is linear function.

Step-by-step explanation:

3 0
3 years ago
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Which would stop a plant from being able to grow?
Nikitich [7]
C: not getting enough sunlight
4 0
4 years ago
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Subtract:<br> -6x-3 from 2x-5
grin007 [14]

Answer:

<h2><u><em>8x -2</em></u></h2>

Step-by-step explanation:

Subtract:

-6x-3 from 2x-5

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6 0
2 years ago
Consider the following binomial experiment. The probability that a green jelly bean is chosen at random from a large package of
Flura [38]

Answer:

There is a 5.79% probability that at most 2 jelly beans are chosen.

Step-by-step explanation:

For each jelly bean chosen, there are only two possible outcomes. Either it is green, or it is not. This is why we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

There are 13 jelly beans, so n = 13.

The probability that a green jelly bean is chosen at random from a large package of jelly beans is 2/5. This means that p = 0.4.

If Sally chooses 13 jelly beans, what is the probability that at most two will be green jelly beans?

This is

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2).

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{13,0}.(0.4)^{0}.(0.6)^{13} = 0.0013

P(X = 1) = C_{13,1}.(0.4)^{1}.(0.6)^{12} = 0.0113

P(X = 1) = C_{13,2}.(0.4)^{2}.(0.6)^{111} = 0.0453

So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0013 + 0.0113 + 0.0453 = 0.0579.

There is a 5.79% probability that at most 2 jelly beans are chosen.

8 0
3 years ago
5. This formula works out the tax you pay.
labwork [276]

Answer:

first you take 5200 and divided by .3 = 17333.33 which is the total of the equation e minus 10600 so that means you have to take 17333.33 and add 10600 which =27933.33= E

6 0
4 years ago
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