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Helga [31]
3 years ago
12

A square picture frame occupies an area of 112 ft2 . What is the length of each side of the picture in simplified radical form?

Show your work
Mathematics
2 answers:
antiseptic1488 [7]3 years ago
8 0
It would be 28 because you have to divide 112 into 4, because the picture is a square(most likely) so its sides are all equal
Kazeer [188]3 years ago
5 0
A = a^2
112 = a^2
sqrt 112 = a
sqrt 16 * sqrt 7 = a
4 sqrt 7 = a

so 4 sqrt 7 is the length of each side
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Jordan wrote the following description: Three fewer than one-fourth of x is 12. Write an equation to represent the description.
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Help me do this …math
Daniel [21]

Step-by-step explanation:

How to find inverse function:

Step 1: Write down equation.

f(x) = 4 \sin(x)  + 3

Remeber Ruler notation that

f(x)=y so we replace y with f(x).

y = 4 \sin(x)  + 3

Next, we must isolate x so first we subtract 3.

y - 3 = 4 \sin(x)

Divide both sides by 4.

\frac{y - 3}{4}  =  \sin(x)

\sin {}^{ - 1} ( \frac{y - 3}{4} )  =  \sin {}^{ - 1} ( \sin(x) )

Remeber that sin^-1x and sin x are inverse functions so they will cancel out to x. So we get

\sin {}^{ - 1} ( \frac{y - 3}{4} )  = x

Swap x and y. So our inverse function is

\sin {}^{ - 1} ( \frac{x - 3}{4} )  = y

If you want another proof: Here's one,

Let plug an a x value for the orginal equation,

4 sin x+3. Let say that

x =  \frac{\pi}{2}

We then would get

4 \sin( \frac{\pi}{2 } )  + 3 = 4 \times (1) + 3 = 4 + 3 = 7

So when x=pi/2, y=7.

By definition of a inverse function, if we let 7 be our input, we should get pi/2. as a output.

So let see.

\sin {}^{ - 1} ( \frac{7 - 3}{4} )  =  \sin {}^{ - 1} ( \frac{4}{4} )  =  \sin {}^{ - 1} (1)  =  \frac{\pi}{2}

So this is the inverse function of 4 sin x+3.

1b. The range of f(x) is [-1,7).

We can use transformations to describe range.

We have

f(x) = 4 \sin(x)  + 3

Parent function is

\sin(x)

with a range of [-1,1].

We then vertical stretch by 4 so we get

4 \sin(x)

and our range will be

[-4,4].

Then we add a vertical shift of 3.

4 \sin(x)  + 3

So our range of 4 sin x+3.

[-1,7].

1c. Domain of a inverse function is the range of the orginal function.

The range of f(x) is [-1,7) so the domain of f^-1(x) is [-1,7].

f(x) domain was restricted to -pi/2 to pi/2 so the range of f^-1(x) is [-pi/2, pi/2]

6 0
2 years ago
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