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Leviafan [203]
2 years ago
7

13x+y=4 plz help i cant get it right lol

Mathematics
2 answers:
kati45 [8]2 years ago
7 0

Answer:

4

__

13

Step-by-step explanation:

look up top for explanation

Gala2k [10]2 years ago
5 0

Answer:

Solve for Y:

Subtract 13x

from both sides of the equation.

y=4−13x

Solve for X:

Move all terms that don't contain x

to the right side and solve.

x=4/13−y/13

Step-by-step explanation:

i think?

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Please help!!! I'm rlly stumped and i don't get this-
Ronch [10]

Answer:

?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The (Figure 1) shows two thin beams joined at right angles. The vertical beam is 19.0 kg and 1.00 m long and the horizontal beam
il63 [147K]

A) The center of gravity of the two joined beams is;

<u><em>(x, y) = (25/44), (19/88)</em></u>

B) The gravitational torque on the joined beams about an axis through the corner is;

<u><em>τ = 245 N.m</em></u>

We are given;

Mass of vertical beam; m₂ = 19 kg

Mass of horizontal beam, m₁ = 25 kg

Length of horizontal beam; L₁ = 2 m

Length of vertical beam; L₂ = 1 m

A) Formula for center of gravity of the two joined beams is;

(x, y) = [(m₁x₁ + m₂x₂)/(m₁ + m₂)],  [(m₁y₁ + m₂y₂)/(m₁ + m₂)]

Where;

(x₁, y₁) is the <em>center of gravity</em> on the <em>horizontal beam</em>

(x₂, y₂) is the <em>center of gravity</em> on the <em>vertical beam</em>

(x₁, y₁) = (L₁/2, 0)

Plugging in the relevant values gives;

(x₁, y₁) = (2/2, 0)

(x₁, y₁) = (1, 0)

(x₂, y₂) = (0, L₂/2)

Plugging in the relevant values gives;

(x₂, y₂) = (0, 1/2)

(x₂, y₂) = (0, 0.5)

Thus, center of gravity of the 2 joined beams is;

(x, y) = [((25 × 1) + (19 × 0))/(25 + 19)],  [((25 × 0)  + (19 × 0.5)))/(25 + 19)]

(x, y) = (25/44), (19/88)

B) Formula for the gravitational torque on the joined beams about an axis through the corner is given as;

τ = (m₁g)x₁ + (m₂g)x₂

Plugging in the relevant values;

τ = (25 × 9.8)1 + (19 × 9.8)0

τ = 245 N.m

Read more at; brainly.com/question/14825257

8 0
1 year ago
HELP ME PLEASE I BEG YOU!!!!!!!!!!
Sav [38]
1X2
b32
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for the first page
8 0
3 years ago
is it possible draw a right triangle with and obtuse angle? if so draw it in the box if not write impossible. is it possible guy
Ipatiy [6.2K]
It is not possible. Since one of the angles has to be a right angle, the other two angles would have to add to 90. Therefore, neither of these angles can be more than 90 degrees. 

Hope this helps
3 0
3 years ago
Help please!!!!!!!!!!
Lelechka [254]

Answer:

I think it's 96 not sure though

3 0
3 years ago
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