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Leviafan [203]
2 years ago
7

13x+y=4 plz help i cant get it right lol

Mathematics
2 answers:
kati45 [8]2 years ago
7 0

Answer:

4

__

13

Step-by-step explanation:

look up top for explanation

Gala2k [10]2 years ago
5 0

Answer:

Solve for Y:

Subtract 13x

from both sides of the equation.

y=4−13x

Solve for X:

Move all terms that don't contain x

to the right side and solve.

x=4/13−y/13

Step-by-step explanation:

i think?

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Each of the line segments in the word MATH are numbered in the graph below. Find the slope (as a ratio of rise over run) of each
emmasim [6.3K]

Answer/Step-by-step explanation:

7. Line 1 = undefined.

Slope of a vertical line is always undefined. The run is zero as x-coordinate remains the same.

8. Line 2 = \frac{4}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 4}{-5 -(-8)}

slope = \frac{8 - 4}{-5 + 8}

slope = \frac{4}{3}

9. Line 3 = \frac{4}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 4}{-2 -(-5)}

slope = \frac{8 - 4}{-2 + 5}

slope = \frac{4}{3}

10. Line 4 = undefined (slope of a vertical line is always undefined)

11. Line 5 = \frac{7}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 1}{5 - 2}

slope = \frac{7}{3}

12. Line 6 = -\frac{7}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 1}{5 - 8}

slope = \frac{7}{-3}

slope = -\frac{7}{3}

13. Line 7 = 0

An horizontal line has no rise.

14. Line 8 = 0 (slope of horizontal line is always zero)

15. Line 9 = undefined (slope of a vertical line is always undefined)

16. Line 10 = undefined (slope of a vertical line is always undefined)

17. Line 11 = 0 (slope of horizontal line is always zero)

18. Line 12 = undefined (slope of a vertical line is always undefined)

5 0
3 years ago
Find an area of a triangle with a base of 25 feet and height of 8 feet. What’s the formula for a triangle?
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Answer:

100 feet squared: can u plz give me the brainliest answer!!!!!!!!! plz!!!!!!!!!!!

Step-by-step explanation:

Area of triangle: base x height divided by 2.

25 x 8 = 200

200/2 = 100

Have a nice day!!!!!!!!!! :-)

<u>KA</u>

4 0
2 years ago
Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of
ser-zykov [4K]

Answer: graph E.


A geometric sequence can be written as:

a_{n} = a_{1} \cdot r^{(n - 1)}

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r = ratio = 0.5


Substituting the numbers, we have:

a_{n} = 4 \cdot (\frac{1}{2})^{n-1}

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f(x) = 4 \cdot (\frac{1}{2})^{x - 1}


This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).


In order to choose between graph B and E, let's evaluate the function in two different points:

f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4

f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.




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