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Leviafan [203]
3 years ago
7

13x+y=4 plz help i cant get it right lol

Mathematics
2 answers:
kati45 [8]3 years ago
7 0

Answer:

4

__

13

Step-by-step explanation:

look up top for explanation

Gala2k [10]3 years ago
5 0

Answer:

Solve for Y:

Subtract 13x

from both sides of the equation.

y=4−13x

Solve for X:

Move all terms that don't contain x

to the right side and solve.

x=4/13−y/13

Step-by-step explanation:

i think?

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Amanda [17]

Answer:

2400 mm

Step-by-step explanation:

(80 x 60) - (60 x 40)

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HELP PLEASE FAST<br> Solve for c. −18c=2 What is the answer? −16 −4 4 16
denpristay [2]
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Read 2 more answers
1+2-3+4+5-6+7+8-9...+97+98-99
zaharov [31]

Answer:

  1584

Step-by-step explanation:

The sum of this sequence can be found a number of ways. One way is to recast it as the series whose terms are groups of three terms of the given series.

__

<h3>series of partial sums</h3>

The partial sums, taken 3 terms at a time, are

  1+2-3 = 0

  4+5-6 = 3

  7+8-9 = 6

...

  97+98-99 = 96

So the original series is equivalent to ...

  0 +3 +6 +... +96 = 3×1 +3×2 +... +3×32 = 3×(1 +2 +... +32)

That is, the sum is 3 times the sum of the consecutive integers 1..32.

__

<h3>consecutive integers</h3>

The sum of integers 1..n is given by the equation ...

  s(n) = n(n+1)/2

__

<h3>series sum</h3>

Using this to find the sum of our series, we find it to be ...

  series sum = 3 × (32)(33)/2 = 1584

_____

<em>Alternate solution</em>

The given series is the sum of integers 1-99, with 6 times the sum of integers 1-33 subtracted. That is, ...

  1 + 2 - 3 + 4 + 5 - 6 = 1+2+3+4+5+6 -2(3 +6) = 1+2+3+4+5+6 -6(1+2)

Continuing on to ...97 +98 -99 gives the result s(99) -6s(33).

Computed that way, we find the sum to be ...

  (99)(100)/2 -6(33)(34)/2 = 4950 -3366 = 1584

3 0
2 years ago
I need help asap please! &lt;3
Olin [163]
Where’s the figure at there’s only the questions
6 0
3 years ago
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