Question

What is the distance between (-6,4) and (-8, 6)?

Answer 1

Answer:

$\sqrt{8}=2\sqrt{2}$

Step-by-step explanation:

by using well known formula, distance on XOY plane

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\=\sqrt{(-8-(-6))^2+(6-4)^2}\\=\sqrt{(-2)^2+(2)^2}$