16 red cars and 12 black cars. He put half of each colour in each box. Therefore he would put 8 red and 6 black in each box. 8 red + 6 black is 14. Therefore he would have 14 cars in each box.
14.
Answer:
The first answer is correct.
Step-by-step explanation:
Line 5 says that the reason is due to substitution
Line 3 says m∠ SQT equals 180°
If we substitute 180° into the spot for m∠ SQT in line 4, we get solution option 1
Answer:
16.....................................
- 6⁹*6ⁿ = 6¹²
- 6⁹⁺ⁿ = ¹²
- 9 + n = 12
- n = 3
17.....................................
- 7⁸/7ⁿ = 7³
- 7⁸⁻ⁿ = 7³
- 8 - n = 3
- n = 5
18.....................................
19.....................................
- 1/10⁵ = 10ⁿ
- 10⁻⁵ = 10ⁿ
- -5 = n
- n = -5
20.....................................
- (8²)ⁿ = 8¹²
- 8²ⁿ = 8¹²
- 2n = 12
- n = 6
The picture below has both of the answers to your problem.
I am thinking it would be 6