We're given LM = NO which will be used in substitution later.
By the segment addition postulate, we can write
LN = LM+MN
which basically says "glue LM and MN together to get LN". All three segments fall on the same line.
Now substitute or replace LM with NO. This works because LM = NO is given
So we go from this
LN = LM+MN
to this
LN = NO+MN
Rearrange terms to go from
LN = NO+MN
to
LN = MN+NO
The formal property used is the "Commutative Property of Addition"
Now notice on the right hand side we can combine MN and NO to get MO. Again this is using the segment addition postulate.
So the last step is going from
LN = MN+NO
to
LN = MO
Have a look at the attached image to see how to format this proof into a two-column proof.
Answer:
product
Step-by-step explanation:
you have to find out 1 year how hiw much interest she pay by finding out the amt of 3.72 %
Answer:
109.899098772yd
Step-by-step explanation:
90-16=74
cos(74)=x/640
Answer:
1/12
Step-by-step explanation:
<u>Needed information</u>

The sum of the probabilities of all outcomes must equal 1
<u>Solution</u>
We are told that the probability that the counter is <em>not</em> black is 3/4.
As the sum of the probabilities of all outcomes <u>must equal 1</u>, we can work out the probability that the counter <em>is </em>black by subtracting 3/4 from 1:


We are told that the probability that the counter is <em>not </em>white is 2/3.
As the sum of the probabilities of all outcomes <u>must equal 1</u>, we can work out the probability that the counter <em>is </em>white by subtracting 2/3 from 1:


We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:
