Question

An equation of a parabola with its vertex at (-3,2) and focus at (-3,-1) written in general equation form

Answer 1

 we have that
standard form of equation for parabola:
 (x-h)^2=-4p(y-k)
(h,k) --------->being the (x,y) coordinates of the vertex.
Parabola opens downwards because focus is below vertex on the axis of symmetry.
For given problem:
vertex: (-3,2)
axis of symmetry: x=-3
p=distance from vertex to focus on the axis of symmetry=2-(-1)=3
4p=12
Directrix: y=2+p=5
Equation:
(x+3)^2=-12(y-2)

the answer is (x+3)^2=-12(y-2)