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vitfil [10]
3 years ago
7

When Asher looks at the data he says that both Mrs. Jamison's class and Mr. Zimmerman's class has data that is skewed right. Do

you agree or disagree? Why or why not?
Mathematics
1 answer:
Yuliya22 [10]3 years ago
5 0

Answer:

Step-by-step explanation:

this isn’t an answer but did u did the answer to this because i need it. thanks

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Simplify the expression. Write the answer without using parentheses or negative exponents.
rodikova [14]
\frac{ (x^4 y^2)^5 }{ (x^2 y)^2 } =\frac{ x^{4*5} y ^{2*5} }{ x ^{2*2} y ^2 } =\frac{ x^{20} y ^{10} }{ x^4y^2 } = x^{20-4} *y^{10-2}= x^{16} *y^{8}


5 0
2 years ago
Which expression is equivalent to negative 32 5/3?
Sloan [31]
Im confused. Its not equal to any of the choices

Unless C  is the cube root of 32^5.

 [t3] \sqrt[n]{x} [32^5]
6 0
3 years ago
Suppose KLMN ~ PQRS. Find the value of x.
arlik [135]

Complete question is attached.

Answer:

B) 8

Step-by-step explanation:

In this question, KLMN ~ PQRS. This means they are similar shapes.

From the image, we could denote that:

KL ~ PQ

LM ~ QR

Given that:

KL = 12

PQ = 30

QR = 20

LM = x

To find x, let's use tge expression:

\frac{KL}{PQ} = \frac{LM}{QR}

=  \frac{12}{30} = \frac{x}{20}

Cross multiplying, we have:

12 * 20 = 30x

240 = 30x

To find x, let's divide both sides by 30.

\frac{240}{30} = \frac{30x}{30}

8 = x

x = 8

The correct option is option B.

3 0
3 years ago
Find the distance between each pair of points. Round your answer to the nearest tenth, if necessary. Hint: Use the Pythagorean T
Paul [167]

The distance between two points on the plane is given by the formula below

\begin{gathered} A=(x_1,y_1),B=(x_2,y_2) \\ \Rightarrow d(A,B)=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2} \end{gathered}

Therefore, in our case,

A=(-1,-3),B=(5,2)

Thus,

\begin{gathered} \Rightarrow d(A,B)=\sqrt[]{(-1-5)^2+(-3-2)^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61} \\ \Rightarrow d(A,B)=\sqrt[]{61} \end{gathered}

Therefore, the answer is sqrt(61)

In general,

-(-n)=n

Remember that

-n=(-1)\cdot n

Therefore,

\begin{gathered} a-(-n)=a+(-1)(-n)=a+(-1)(-1\cdot n)=a+(-1)^2\cdot n=a+1\cdot n=a+n \\ \Rightarrow a-(-n)=a+n \end{gathered}

6 0
1 year ago
What is the answer to page 156-157 on chapter 4 proportions relationship.
timurjin [86]
Proportional relationships<span>: A </span>relationship<span> between two equal ratios. Proportions are the comparison of two equal ratios. Therefore, </span>proportionalrelationships<span> are </span>relationships<span> between two equal ratios. For example, oranges are sold in a bag of 5 for $2. The ratio of oranges to their cost is 5:2 or.</span><span>In mathematics, two variables are proportional if a change in one is always accompanied by a change in the other, and if the changes are always related by use of a constant multiplier. The constant is called the coefficient of proportionality or proportionality constant.</span>
4 0
3 years ago
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