Use the Pythagorean Theorem of a² + b² = c² to solve for x.
x² + (x + 3)² = (√117)²
x² + x² + 6x + 9 = 117
2x² + 6x + 9 = 117
2x² + 6x + 9 - 117 = 0
2x² + 6x - 108 = 0
2x² + 18x - 12x - 108 = 0
2x(x + 9) - 12(x + 9) = 0
(2x - 12)(x + 9) = 0
x = - 9, 6
Length cannot be negative so you can't use - 9.
x = 6. Option C is your answer.
Answer:
![\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D%3D%28a%5E%7B2%7D%2Bb%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Step-by-step explanation:
∵∛x = (x)^1/3
∴
So you can replace the radicals by fractional exponents
Answer:
A. Kayla
Step-by-step explanation:
To find the difference between the two numbers we will do:
7°C - (-5°C)
Subtracting a negative number is the same as simply adding, so we can rewrite the equation as:
7°C + 5°C = 12°C
Answer:
15.09
Step-by-step explanation:
with reference angle 28°
perpendicular (p) = 8
base (b) = x
Now
tan 28° = p / b
0.53 = 8 / x
x = 8 / 0.53
x = 15.09
The answered the question is X=5
