Question

What is the area of a rectangle with length 4x-3 and width 6x+9

Answer 1

Area of the rectangle is 24x²+18x-27

Answer 2

We are given

length of rectangle is 4x-3

width of rectangle is 6x+9

we know that

Area of rectangle = length of rectangle*width of rectangle

so, we can plug value

and we get

$Area=(4x-3)*(6x+9)$

now, we can distribute it

$Area=4x*6x+4x*9-3*6x-3*9$

now, we can simplify it

$Area=24x^2+36x-18x-27$

$Area=24x^2+18x-27$...............Answer