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LuckyWell [14K]
3 years ago
11

Use a system of linear equations with two variables and two equations to solve.

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0

Answer:

passed: 164

failed: 41

Step-by-step explanation:

Let the failed students be x, then the passed students will be 4x.

x + 4x = 205

x = 205/5 = 41

4x = 4*41 = 164

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The questions is on the picture
allochka39001 [22]

Answer:

EASY:

Step-by-step explanation:

-7 > -12    

2 > -2

-5 < -3

|-9| is maybe 9.

|13| is 13.

|-5| is maybe 5.

5 0
3 years ago
Read 2 more answers
Suppose that you are a city planner who obtains and sample of 20 randomly selected members of a mid-sized town in order to deter
Dmitry_Shevchenko [17]

Answer:

The critical value for the 95% confidence interval is z = 1.96.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96.

The critical value for the 95% confidence interval is z = 1.96.

5 0
3 years ago
When studying radioactive​ material, a nuclear engineer found that over 365​ days, 1,000,000 radioactive atoms decayed to 973 co
HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

N(t)=N0*e^{kt} where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

1,000,000=N0*e^{k*0}

1,000,000=N0

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

973,635=1,000,000*e^{k*365}

ln(973,635/1,000,000)/365=k

-0.0000732=k

A. atoms decayed in a day:

N(t)=1,000,000*e^{-0.0000732t}

N(1)=1,000,000*e^{-0.0000732*1}

N(1)= 999,926.803

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0
3 years ago
To change the 0.32 into percentage, I need to
Westkost [7]
Move the dot twice to the right
7 0
2 years ago
The soccer team collected $800 at a car wash fundraiser. They charged $5.00 for small vehicles and $10.00 for longer vehicles. T
Dahasolnce [82]

There are 160 small cars that were washed because u divide

800/ 5= 160. :P

Hope this helps you!!

4 0
3 years ago
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