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3 years ago

Use a system of linear equations with two variables and two equations to solve.

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

7 0

Answer:

passed: 164

failed: 41

Step-by-step explanation:

Let the failed students be x, then the passed students will be 4x.

x + 4x = 205

x = 205/5 = 41

4x = 4*41 = 164

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If x2 = 10, what is the value of x?

JulsSmile [24]

If you mean x^2 then there would be no answer after all, 3^2= 9 and 4^2= 16 so

If you mean 2x then the answer would be 5

Hope I helped?

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3 years ago

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In how many ways can the first 4 guests arrive at a party if 15 guests have been invited.

notsponge [240]

Answer:

The first 4 guests can arrive in 32,760 ways.

Step-by-step explanation:

The order in which the guests arrive is important. For example, A,B,C,D is a different outcome to B,A,C,D. So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

In this question:

4 guests from a set of 15. So

$P_{(15,4)} = \frac{15!}{(15-4)!} = 32760$

The first 4 guests can arrive in 32,760 ways.

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4 years ago

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John opened a savings account with an interest rate of 2.25%. If he deposited $80 in the account when he opened it and did not m

Y_Kistochka [10]

Answer:

Step-by-step explanation:

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3 years ago

Find the next two numbers in the pattern -128,64,-32,16

Tems11 [23]

Answer:

Step-by-step explanation:-8

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4 years ago

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The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$

So the correct option is 4

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3 years ago

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