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neonofarm [45]
3 years ago
5

In Greg's that, he has $1$ yellow, $2$ red, and $3$ green tokens. One red token is equivalent to $7$ yellow tokens. One yellow t

oken is equivalent to $3$ green tokens. Greg converts all of his tokens to green tokens. How many green tokens does he have?

Mathematics
2 answers:
JulsSmile [24]3 years ago
8 0

Answer:

48

Step-by-step explanation:

vodka [1.7K]3 years ago
4 0

Answer:

$48 green tokens

Step-by-step explanation:

please check the attached file for explanation

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Billie’s monthly cell phone bill includes the cost of cell phone service, 15% tax on the cost of the cell phone service, and a $
Mashcka [7]
<em>It would be $46 because when you add the 15% tax to it, the total is $61. </em>
<em>$61-15%=$46. To check $46+15%=61! Hope i helped! :-)</em>
4 0
3 years ago
Can anyone help me solve this
kumpel [21]

Answer:

The answer to your question is a = 40, b = 5/8

Step-by-step explanation:

Data

  ab = 25

  log₄a - log₄b = 3

Process

1.- Use the law log of a quotient

               log₄ a/b = 3

2.- Convert the log to an exponent

                   a/b = 4³

                   a/b = 64      Equation l

                    ab = 25       Equation ll

3.- Solve equation l for a

                  a = 64b

4.- Substitute in equation ll

                   (64b)b = 25

-Simplify

                    64b² = 25

-Solve for b

                         b² = 25/64

                         b = 5/8

5.- Substitute the value of b to find a

                     a = 64(5/8)

-Simplification

                     a = 40                        

4 0
3 years ago
Show that if X is a geometric random variable with parameter p, then
Lubov Fominskaja [6]

Answer:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

X\sim Geo (1-p)

In order to find the expected value E(1/X) we need to find this sum:

E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}

Lets consider the following series:

\sum_{k=1}^{\infty} b^{k-1}

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}   (a)

On the last step we assume that 0\leq r\leq b and \sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}, then the integral on the left part of equation (a) would be 1. And we have:

\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)

And for the next step we have:

\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}

And with this we have the requiered proof.

And since b=1-p we have that:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

4 0
3 years ago
SOMEONE PLS HELP :(!!!!!!
diamong [38]
It would be C as the answers
6 0
2 years ago
Please help me with this logs question!
Temka [501]
no1 is the answer......
6 0
3 years ago
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