Answer:
The answer is, " About 56% of those who prefer baseball are eight graders"
Step by Step Explanation:
Step 1: Turn 56% to a decimal, you get 0.56
Step 2: Multiply 0.56 by 68, the total amount of people who like baseball
Step 3 : you get 38.08 ( Don't mind the extra .08, just round )
Step 4 : You celebrate with a little victory dance!!!!!
Answer:
0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.
Step-by-step explanation:
The following information is missing:
The standard deviation of population is 100.
We are given the following information in the question:
Population mean, μ = 502
Standard Deviation, σ = 100
Sample size, n = 90
Standard error =

Formula:

P(test score within 10 points)


0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.
Answer:
10 cent increase
Step-by-step explanation:
0.89
<u>-0.79</u>
0.10
or 7.89%
Teachers and principles probably still want to keep school a little old fashioned while still having little technology by the next year or 2 we'll might not have to carry heavy backpacks anymore I wish you the best of luck.