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3 years ago

77,098 rounded to the nearest thousand

Mathematics

2 answers:

quester [9]3 years ago

6 0

77,098 is closer to 77,000 than it is to 78,000, so rounded to the nearest thousand it would be 77,000.

anastassius [24]3 years ago

5 0

77,098 would be rounded to 77,000. look at the hundredths place if its 4 then down, 5 up

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koban [17]

Answer:

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Step-by-step explanation:

Given

$A = (-1,-2)$

$B = (2,4)$

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Required

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$\frac{AP}{BP} = \frac{1}{2}$

Cross multiply

$2AP = BP$

Calculate AP and BP using the following distance formula:

$d = \sqrt{(x - x_1)^2 + (y - y_1)^2}$

So, we have:

$2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

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$4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2$

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Collect and evaluate like terms

$4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20$

Open brackets

$4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20$

Collect like terms

$4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y + 20 - 20 = 0$

$3x^2 + 12x + 3y^2 +24y = 0$

Divide through by 3

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2 years ago

The value of a second-hand car is £8000. Each year it loses 20% of its value at the start of this year. work out its value in 5

Elodia [21]

Answer:

the value in the five years is £2,621.44

Step-by-step explanation:

The computation of the value in the five years is given below:

= The value of the second car × (1 - losses percentage)^number of years

= £8,000 × (1 - 0.20)^5

= £8,000 × 0.80^5

= £8,000 × 0.32768

= £2,621.44

Hence, the value in the five years is £2,621.44

We simply applied the above formula so that the correct value could come

And, the same is to be considered

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creativ13 [48]

Answer: X=18

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2 years ago

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Answer:

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