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blsea [12.9K]
3 years ago
15

The slope of the line shown in the graph is ? and the y intercept of the line is ?

Mathematics
1 answer:
ohaa [14]3 years ago
5 0
Pick 2 points on ur line and use the slope formula : (y2 - y1) / (x2 - x1)

(y2 - y1) / (x2 - x1)
(-9,0)....x1 = -9 and y1 = 0
(0,6).... x2 = 0 and y2 = 6
now sub
slope = (6 - 0) / (0 - (-9) = 6/(0 + 9) = 6 / 9 = 2/3 <==

ur y intercept is where ur line crosses the y axis...and that would be (0,6)....or just 6 <==

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Lets make the graph of our systems of equations:

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7 0
11 months ago
State whether the following coordinates on a Cartesian plane form an acute, obtuse or right triangle: a) (-1, 1), (7,-2) and (1,
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Answer:

a) Acute triangle

b) Right triangle

Step-by-step explanation:

∵ A triangle having sides a, b and c is called,

Acute : If a² + b² > c² or a² + c² > b² or b² + c² > a²,

Obtuse : if a² + b² < c² or a² + c² < b² or b² + c² < a²

Right : a² + b² = c² or a² + c² = b² or b² + c² = a²,

a) Let A≡(-1, 1), B≡(7,-2) and C≡(1,-5),

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AB=\sqrt{(7-(-1))^2+(-2-1)^2}=\sqrt{(7+1)^2+(-3)^2}=\sqrt{8^2+3^2}=\sqrt{64+9}=\sqrt{73}\text{ unit}

Similarly,

BC=\sqrt{45}\text{ unit}

CA=\sqrt{40}\text{ unit}

∵ The sum of any two sides is greater than third side,

So, ABC is a triangle,

Now,

AB^2 + BC^2 > CA^2

⇒ ABC is an acute triangle.

b) Let P≡(0,6), Q≡(1,2) and R≡(5,3),

By the distance formula,

PQ = √17 unit,

QR = √17 unit,

RP = √34 unit,

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3 0
3 years ago
Please help me out!!!!!!
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a=h=12

we plug these numbers into the formula for the volume of a pyramid and get:

400

3 0
3 years ago
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4 0
3 years ago
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