All categories

3 years ago

Solve 4x−9y=13 for y.

Mathematics

1 answer:

Irina18 [472]3 years ago

8 0

Answer:

$y = - \frac{13}{9} + \frac{4}{9} x$

Step-by-step explanation:

$4x - 9y = 13$

$4x - 9y - 4x = 13 - 4x$

$- 9y = 13 - 4x$

$y = 9y \div (9) = (13 - 4x) \div ( - 9)$

$y = (13 - 4x) \div( - 9)$

$y = 13 \div ( - 9) - 4x \div ( - 9)$

$y = - 13 \div 9 - 4x \div ( - 9)$

$y = - \frac{13}{9} - 4x \div ( - 9)$

$y = - \frac{13}{9} + 4x \div 9$

$\boxed{\green{y = - \frac{13}{9} + \frac{4}{9} x, x E R}}$

You might be interested in

HELPPPP- you just got your driver's license. Your parents buy you a car and agree to let you pay them back over a period of 70 m

Nitella [24]

Using the monthly payments formula, it is found that a car with a value of at most $25,293.

<h3>What is the monthly payment formula?</h3>

It is given by:

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

In which:

P is the initial amount.

r is the interest rate.

n is the number of payments.

In this problem, we have that the parameters are given as follows:

A = 400, n = 70, r = 0.035.

Hence:

r/12 = 0.035/12 = 0.002917.

Then we have to solve for P to find the maximum value of the car.

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

$400 = P\frac{0.002917(1.002917)^{70}}{(1.002917)^{70}-1}$

$P = \frac{400[(1.002917)^{70}-1]}{0.002917(1.002917)^{70}}$

P = $25,293.

More can be learned about the monthly payments formula at brainly.com/question/26267630

#SPJ1

7 0

1 year ago

What is the percent increase 41,700 and 63,00

valentinak56 [21]

Answer:

51.0791%

Step-by-step explanation:

Calculate percentage change

from V1 = 41700 to V2 = 63000

(V2−V1)|V1|×100

=(63000−41700)|41700|×100

=2130041700×100

=0.510791×100

=51.0791%change

=51.0791%increase

7 0

3 years ago

An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W. From pre

Shtirlitz [24]

Answer:

Null Hypothesis, $H_0$ : $\mu \leq$ 250 W

Alternate Hypothesis, $H_A$ : $\mu$ > 250 W

Step-by-step explanation:

We are given that an appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W.

They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.

Let $\mu$ = mean power consumption of microwave ovens.

So, Null Hypothesis, $H_0$ : $\mu \leq$ 250 W

Alternate Hypothesis, $H_A$ : $\mu$ > 250 W

Here, null hypothesis states that the mean power consumption of microwave ovens is no more than 250 W.

On the other hand, alternate hypothesis sates that the mean power consumption of microwave ovens is more than 250 W.

The test statistics that would be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

Hence, this would be the appropriate hypotheses to determine if the manufacturer's claim appears reasonable.

5 0

3 years ago

At the beginning of each year for 14 years, Sherry Kardell invested $400 that earns 10% annually. What is the future value of Sh

Naddik [55]

Hmm if I'm not mistaken, is just an "ordinary" annuity, thus

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]
\\\\\\$

$\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array} &
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &400\\
r=rate\to 10\%\to \frac{10}{100}\to &0.1\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, so once}
\end{array}\to &1\\

t=years\to &14
\end{cases}
\\\\\\
A=400\left[ \cfrac{\left( 1+\frac{0.1}{1} \right)^{1\cdot 14}-1}{\frac{0.1}{1}} \right]
$

3 0

3 years ago

Read 2 more answers

What is 4/6 ÷8/14???????????????

Morgarella [4.7K]

Answer:

7/6

Step-by-step explanation:

4/6 divided by 8/14

4/6 * 14/8

56/48

Simplified: 7/6