Answer <br> Sssssssssssss

Find the amplitude of the sine curve shown below. a. 3 b. p c. 1.5 d. 6

Nezavi [6.7K]

Answer:

Amplitude = 3

Step-by-step explanation:

Given

The sine curve above

Required

Determine the amplitude

To determine the amplitude of a sine curve, we have to calculate the distance between the horizontal line of the curve and the top or bottom of the function

Using the top of the curve as a point of reference;

Amplitude = Top of curve - Horizontal Line.

The horizontal line is always at point 0

From the graph above, the top of the curve is at point 3

Hence,

Amplitude = 3 - 0

Amplitude = 3

3 0

4 years ago

A polynomial has been factored, as shown below: f(x) = (x − 9)(x + 12)(x − 24) What are the zeros of the polynomial? (5 points)

Alekssandra [29.7K]

Answer:

The answer is Option c

9, -12, 24

Step-by-step explanation:

We have the polynomial:

$f(x) = (x - 9)(x + 12)(x - 24)$

To find the zeros we must equal $f(x) = 0$

So:

$(x - 9)(x + 12)(x - 24) = 0$

Then the previous expression is equal to zero in any of these 3 cases:

$(x-9) = 0\\x = 9$

$(x + 12) = 0\\x = -12$

$(x-24) = 0\\x = 24$

Then $f(x) = 0$ if $x = 9$ or $x = -12$ or $x = 24$

The answer is 9, -12, 24

5 0

3 years ago

Let f(x)=−7, g(x)=−4x+5 and h(x)=4x2−8x−5. Consider the inner product 〈p,q〉=p(−1)q(−1)+p(0)q(0)+p(1)q(1) in the vector space P2

Levart [38]

Answer:

The basis is <1/√3, -2/5 x + 1 /15, 0.4825x^2 - 0.6466 x -0.3748>

Step-by-step explanation:

First, we calculate the norm of f

||f||² = <f,f> = f(-1)²+f(0)²+f(1)² ) = 3*(-7)² = 147

Therefore, ||f|| = √147

We take as the first element of the basis $\frac{-7}{\sqrt{147}} = \frac{1}{\sqrt{3}} .$

we define

$\tilde{g}(x) = g(x) - * v1$

lets calculate <g,v1>

g(-1) = 9

g(0) = 5

g(1) = 1

v1(-1) = v1(0) = v1(1) = 1/√3

Then <g,v1> = 9*7/√(147)+5*7/√(147)+1*7/√(147) = 15*7/√(147) = 105/√147

and <g,v1>v1 = 105/√(147) * 7/√(147) = 735/147 = 35/9

Therefore,

$\tilde{g}(x) = -4x+5-35/9 = -4x + 2/3$

Now, lets calculate the norm, for that

$\tilde{g}(-1) = 14/3$

$\tilde{g}(0) = 2/3$

$\tilde{g}(1) = -10/3$

As a result, $< \tilde{g}, \tilde{g} > = (14/3)^2+(2/3)^2+(-10/3)^2 = 100, hence [tex] || \tilde{g} || = 10$

We take $v2 = \tilde{g} / 10 = -2/5 x + 1 /15$

Finally, we take

$\tilde{h}(x) = h(x) - v1 - v2$

Note that

h(-1) = 7

h(0) = -5

h(1) = -9

v1(-1) = v1(0) = v1(1) = 7/√(147) = 1/√3

v2(-1) = 7/15

v2(0) = 1/15

v3(1) = -1/3

Thus,

<h,v1>v1 = (7-5-9)*(7/√(147))² = -7/3

<h,v2>v2 = ((7*7/15) + (-5*1/15) + (-9*-1/3)) * (-2/5 x + 1 /15) = -66/25 x + 11/25

As a consecuence, we have that

$\tilde{h}(x) = 4x^2-8x-5 +7/3 + 66/25x -11/25 = 4x^2-5.36x-233/75$

since

$\tilde{h} (-1) = 469/75; \tilde{h} (0) = 233/75: tilde{h}(1) = -67/15$

we obtain that $||\tilde{h}|| = \sqrt{} = \sqrt{86.706} = 8.288$

Therefore, $v3 = \tilde{h}/8.288 = (4x^2-5.36x-233/75)/8.288 = 0.4825x^2 - 0.6466 x -0.3748$

The basis is <1/√3, -2/5 x + 1 /15, 0.4825x^2 - 0.6466 x -0.3748>

4 0

3 years ago

What is the product of negative 1/4 multiplied by negative 3/7?

Bond [772]

Let's set x being the product, then:

x = (-1/4) . (-3/7)

x = 3/28

Hope it helps.

3 0

3 years ago

Read 2 more answers

Find the length of the segment indicated. Round to the nearest tenth if necessary.

Artemon [7]

Step-by-step explanation:

<h2><u>Given-</u></h2>

The length of the segment of the chord DB is 8.2 units.

The length of the segment AB is 6.9 units.

The length of the radius AC be x units.

We need to determine the value of x.

Length of BC:

Since, we know the property that, "if a radius is perpendicular to the chord, then it bisects the chord".

Thus, applying the above property, we have;

DB ≅ BC

8.2 = BC

Thus, the length of BC is 8.2 units.

Value of x:

Since, ∠B makes 90°, let us apply the Pythagorean theorem to determine the value of x.

Thus, we have;

AC^2=AB^2+BC^2AC

2

=AB

2

+BC

2

Substituting the values, we have;

x^2=6.9^2+8.2^2x

2

=6.9

2

+8.2

2

x^2=47.61+67.24x

2

=47.61+67.24

x^{2} =114.85x

2

=114.85

x=10.7x=10.7

Thus, the value of x is 10.7 units.

/dab

6 0

2 years ago

Answer Sssssssssssss