Answer:
The weight of cat is <u>14 pounds</u> and the weight of kitten is <u>4 pounds</u>.
Step-by-step explanation:
Given:
Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.
Now, to find the weight of each animal:
Let the cat's weight be 
And the kitten weight = 
Total weight of cat and kitten = 18 pounds.
Now, to set an equation to get the weight of each animal:




<em>Multiplying both sides by 2 we get:</em>
<em />
<em />
<em>Adding both sides by 6 we get:</em>
<em />
<em />
<em>Dividing both sides by 3 we get:</em>
<em />
<em />
<em>The weight of cat = 14 pounds.</em>
Substituting the value of
to get the kitten's weight:

<em>The kitten's weight = 4 pounds.</em>
Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.
Answer:
The coordinates of point B are (-3,-3).
Step-by-step explanation:
Let
,
and
, then we have the following formula by vectorial definition of a line segment:

![B(x,y) -A(x,y) = \frac{3}{4}\cdot [C(x,y)-A(x,y)]](https://tex.z-dn.net/?f=B%28x%2Cy%29%20-A%28x%2Cy%29%20%3D%20%5Cfrac%7B3%7D%7B4%7D%5Ccdot%20%5BC%28x%2Cy%29-A%28x%2Cy%29%5D)



Step-by-step explanation:
....................
Perpendicular lines is e
Angle is c
Line segment is a
Parallel lines is h
Circles is f
For this case we must indicate the factors of the following expression:

To factor we must find two numbers that when multiplied result in -20 and when added, result in -12.
There are no two numbers that meet this condition. Thus, the expression is not factorizable with rational numbers.
Answer:
The expression is not factorizable with rational numbers.