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PolarNik [594]
3 years ago
14

4 1/3×2 3/4. this is 6 grade math

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0
11 11/12 is the answer
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Find the value for x. Round your answer to the nearest hundredth. Area of the triangle = 8 ft^2​
zmey [24]

Answer:

x = 3.51

Step-by-step explanation:

Since, formula to determine the area f a triangle is,

Area = \frac{1}{2}(\text{Base})(\text{Height})

     8 = \frac{1}{2}(x + 1)(3x - 7)

16 = x(3x - 7) + 1(3x - 7)

16 = 3x² - 7x + 3x - 7

16 = 3x² - 4x - 7

0 = 3x² - 4x - 23

3x²- 4x - 23 = 0

By quadratic formula,

x = \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

x = \frac{4\pm \sqrt{(-4)^{2}-4(3)(-23)}}{2(3)}

x = \frac{4\pm \sqrt{292}}{6}

x = \frac{4\pm 17.09}{6}

x = 3.51, -2.18

But the length of sides can't be negative.

Therefore, x = 3.51 will be the answer.

8 0
2 years ago
F(x) = (4x–5)/6 <br> Find the Inverse
noname [10]

Answer:

F^-1 (x) = 3x/2+5/4

Step-by-step explanation:

First, replace f(x) with y

Replace every x with a y and replace every y with an x .

Solve the equation from Step 2 for y  

Replace y with f−1(x) f − 1 ( x )

Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.

Hope this helps!  Stay Safe!

3 0
2 years ago
Using graph paper, determine the line described by the given point and slope. Click to show the correct graph below.
Alenkinab [10]

Answer:

Probably the 1st picture.

Step-by-step explanation:

keep in mind, the center is 0.

7 0
2 years ago
How do i find the ratio 2:9
Ganezh [65]
The ratio of 2:9 has to be 2:9 do to the fact you can't simplify the fraction 2/9.
Hoped I helped.
6 0
3 years ago
A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7). What are the vertices of r(90, O)(WXYZ)?
VashaNatasha [74]

Given:

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).

Rule of rotation is r_{(90^\circ, O)}(WXYZ).

To find:

The vertices after rotation.

Solution:

We know that, r_{(90^\circ, O)}(WXYZ) means 90 degrees counterclockwise rotation around the origin.

So, the rule of rotation is defined as

(x,y)\to (-y,x)

Using this rule, we get

W(3,-5)\to W'(5,3)

X(1,-3)\to X'(3,1)

Y(-1,-5)\to Y'(5,-1)

Z(1,-7)\to Z'(7,1)

Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).

8 0
3 years ago
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