There’s a pattern to this and I’ll explain in the comments if you want to know or can’t figure it out :)
1.) 27/x^3
2.) a^8/b^12
3.) 7^36/81 OR 13,841,287,201/81
4.) 256m^20/n^4
5.) x^6y^6
6.) 64k^4/k^6
7.) 1,000a^9b^6/a^6b^9
8.) 81x^21/625
9.) 2304/x^16y^12
10.) x^7z^14/y^21
11.) 7,776k^5
12.) x^24y^24/4,096
Hope it’s all helped
Find the area of the triangles and smal ler square and add them together ; and find the area of the complete square and set them equal to each other (these are known truths)
triangle: l×w /2
square: s^2
There are 4 triangles so
4 (1/2ab)+c^2= (a+b)(a+b)
simplify
2ab+c^2= a^2+2ab+b^2
-2ab both sides
c^2=a^2+b^2
tada!! it's proven :)
Answer:
The coordinates of A could be anything in the form of (x, y, z) if you have a third axis. First you count where A is on the x-axis then the y-axis and if you have a 3-dimensional graph then the z-axis.
Step-by-step explanation:
