Answer:
Imagine an easier version of this problem: You have a board 5 feet long that you must cut (divide, right?) into two equal parts. It is probably clear to you that you simply divide the length (5) by the number of parts you're dividing it into (2) to obtain the length of each piece (2.5 feet).
Use the same method for your problem 5 feet divided by 6 is 0.83 feet per piece.
We do not ordinarily divide feet into decimal portions, but instead into inches. Since an inch is 1/12 of a foot, you could simply say 5/6 = how many twelfths? or 5/6 = n/12 Solve this by inspection or by cross multiplying 5 times 12 equals n times 6. So n must equal 10, and your pieces of board are each 10 inches long.
Answer:
Transitive Property
Step-by-step explanation:
Since X is the midpoint, it bisects the points RS. If MX=XS, and RS is the same as XS, then they are the same. This also follows the Transitive propety (if a=b and b=c, then a=c)
Answer:
What are you trying to find?
Step-by-step explanation:
Question:
If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.
Answer:


Step-by-step explanation:
Given
cos(θ) =-8/17
Required
sin(θ) = __
tan(θ) =__
The first step is to determine the length of the third side
Given that

Where Adj and Hyp represent Adjacent and Hypotenuse

By comparison

Using Pythagoras

By Substitution


Subtract 64 from both sides


Take square roots of both sides




The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such

From trigonometry


Also from trigonometry






Answer:
The frequency of the car is 0.0233743 laps/sec and 1.4024 laps were completed in 60 seconds