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qwelly [4]
3 years ago
6

Which statement about the function is true?

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

The answer is The function is decreasing for all real values of x

where

-1<x<4.

Step-by-step explanation:

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How is the sum expressed in sigma notation?<br><br> 11 + 17 + 23 + 29 + 35 + 41
Ann [662]
<h3>The sum expressed in sigma notation is:</h3>

11+17+23+29+35+41=\sum\limits_{i=1}^{6}5+6i

<u><em>Solution:</em></u>

Given that,

11 + 17 + 23 + 29 + 35 + 41

We have to express the sum in sigma notation

Analyse the series

5 + 6(1) = 11

5 + 6(2) = 17

5 + 6(3) = 5 + 18 = 23

5 + 6(4) = 5 + 24 = 29

5 + 6(5) = 5 + 30 = 35

5 + 6(6) = 5 + 36 = 41

<em><u>Thus the series goes on like this:</u></em>

5 + 6(n) , where n = 1 to 6

<em><u>This can be expressed in sigma notation as:</u></em>

11+17+23+29+35+41=\sum\limits_{n=1}^{6}5+6n

<em><u>We can expand the sigma notation and verify the results</u></em>

\sum\limits_{i=1}^{6}5+6i=(5+6(1))+(5+6(2))+(5+6(3))+(5+6(4))+(5+6(5))+(5+6(6))\\\\\\\sum\limits_{i=1}^{6}5+6i=(5+6)+(5+12)+(5+18)+(5+24)+(5+30)+(5+36)\\\\\\\sum\limits_{i=1}^{6}5+6i=11+17+23+29+35+41

8 0
3 years ago
Read 2 more answers
If the volume of a sphere is equal to the volume of a cube, what is the ratio of the edge of the cube to the radius of the spher
Pachacha [2.7K]

Answer: The answer is (C) 1.61.

Step-by-step explanation: Given that the volume of a sphere is equal to the volume of a cube. We are to find the ratio of the edge of the cube to the radius of the sphere.

Let, 'r' be the radius of the sphere and 'e' be the edge of the cube. Then, the volume of the sphere is given by

V_s=\dfrac{4}{3}\pi r^3,

and the volume of the cube is

V_c=e^3.

According to the question, we have

V_s=V_e\\\\\Rightarrow \dfrac{4}{3}\pi r^3=e^3\\\\\\\Rightarrow \dfrac{4}{3}\times\dfrac{22}{7}r^3=e^3\\\\\\\Rightarrow 88r^3=21e^3\\\\\Rightarrow 4.44r=2.75e\\\\\Rightarrow \dfrac{e}{r}=\dfrac{4.44}{2.75}\\\\\Rightarrow e:r=1.61.

Thus, the correct option is (C) 1.61.

4 0
3 years ago
Show that B = {[a, b) ⊂ ℝ | a &lt; b} is a basis for a topology on ℝ
loris [4]

Answer:

Remember that a set \mathcal{B} is a base for some topology on \mathbb{R} if satisfy the following properties:

1. \mathbb{R}=\cup\{B: B\in\mathcal{B}\}

2. For B, B^* \in \mathcal{B}, If p\in B\cap B^* then exist B_p\in\mathcal{B} such that p\in B_p\subset B\cap B^*.

Now, for B=\{[a,b)\subset\mathbb{R}| a < b\} we verify the above properties:

1. It's clear that \mathbb{R}=\cup_{a,b \text{ with }a

2. Let B=[a,b), B^*=[c,d) \in \mathcal{B}, p\in B\cap B^*. Without loss of generality suppose that a. Then c\leq p < b, this implies that p\in[c,b) and B_p=[c,d) \in \mathcal{B} and B_p\subset B\cap B^*.

Then, B satisfy the two properties. This show that B is a basis for a topology in \mathbb{R}

6 0
3 years ago
PLEASE HELP ASAP
oksano4ka [1.4K]

Answer:

B

Step-by-step explanation:

need the length and height of the triangle on the left

3 0
3 years ago
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. (07.01) Karolyn is arranging her art project, science project, and math project on her desk. The tree diagram below shows the
mash [69]

The tree diagram shows that there are a total of six sample spaces.

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  science---math

 

  art---math

 science

 

  math---art

 

  art---science

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 science---art

 

 Based on the tree diagram, the probability that the science project is first is two over six. This is because science appears first in two out of the six sample spaces (boldened).

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4 years ago
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