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3 years ago

What is the x-intercept of the graph of the function f(x) = x^2 − 16x + 64?

Mathematics

1 answer:

kumpel [21]3 years ago

7 0

Answer:

Step-by-step explanation:

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What is the rate of change ?

postnew [5]

The rate of change is also called the slope
the formula foe the rate of change is (y2-y1) / (x2-x1)

x1 = -3
x2 = 6
y1 = 14
y2 = -1
rate of change = (-1 - 14) / (6- (-3)
= -15 / 9
= -5/3

3 0

3 years ago

A rectangle has a height of a² + 3 and a width of a² + 2a + 5.

valentina_108 [34]

Answer:

Area = $a^4+2a^3+8a^2+6a+15$

Step-by-step explanation:

The area of a rectangle is given by:

Area = Height * Width

The expressions for height and width are given. We just need to multiply and add like terms (if applicable) to find the expression for the area of the rectangle.

Remember to use distributive property:

$(a+b)(x+y) = ax + ay + bx + by$

Thus, we have:

$(a^2+3)(a^2+2a+5)\\=(a^2)(a^2)+(a^2)(2a)+(a^2)(5)+3a^2+6a+15\\=a^4+2a^3+5a^2+3a^2+6a+15\\=a^4+2a^3+8a^2+6a+15$

THis is the expression for area.

5 0

3 years ago

Write 0.9 as a fraction with a denominator of 10

adelina 88 [10]

The answer is 9/10
the denominator is on the bottom

5 0

2 years ago

Read 2 more answers

Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.

pashok25 [27]

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

$a\cdot b=0$

By using the property

$(u+v)\cdot (u-v)=0$

We know that

$(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2$

$\mid u\mid ^2-\mid v\mid^2=0$

$\mid u\mid^2=\mid v\mid^2$

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

$\mid u\mid=\mid v\mid$

Hence, the length of vectors u and v must have the same length.

5 0

3 years ago

how does the appearence of a histogram change when u use many small intervals then when you use a few large intervals

vampirchik [111]

If you're using a few larger intervals, then your histogram looks more stocky. If you imagine drawing one, it's because you're adding more values into the same category which can make the difference between two intervals much more noticeable. If you're using smaller intervals, however, you can much more accurately assess the difference between two different intervals. For that reason, the transition between one and another interval would look much more 'fluid'.

5 0

3 years ago