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zheka24 [161]
3 years ago
13

What is the length of segment LP? A. 13.75 in B. 1.75 in C. 35.2 in D. 23.2 in

Mathematics
1 answer:
zavuch27 [327]3 years ago
8 0
Check the picture below.

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What is equivalent to 36/54
mina [271]

Answer:

18/27 would be a equivalent fraction to 36/54

Step-by-step explanation:

36/2=18 and 54/2=27

Therefore, 18/27

5 0
4 years ago
Translation of a 2D shape..<br> Due in tomorrow, please help! Xx
bazaltina [42]
(5,7) (5,4) (7,4) hope that helps
4 0
4 years ago
A rectangular swimming pool that is 10 ft wide by 16 ft long is surrounded by a cement sidewalk of uniform width. If the area of
Alchen [17]
We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.

The value of x is <span>5 feet. </span>

5 0
3 years ago
Which of the following sets of numbers could be the lengths of the sides of a triangle?
just olya [345]

Answer:

  E.  2, 3, 4

Step-by-step explanation:

The sum of the shortest two sides must exceed the longest side. That is only the case for the set ...

  {2, 3, 4}

7 0
3 years ago
How many different ways are there to choose a subset of the set {1,2,3,4,5,6} so that the product of the members of the subset i
zvonat [6]

You have to pick at least one even factor from the set to make an even product.

There are 3 even numbers to choose from, and we can pick up to 3 additional odd numbers.

For example, if we pick out 1 even number and 2 odd numbers, this can be done in

\dbinom 31 \dbinom 32 = 3\cdot3 = 9

ways. If we pick out 3 even numbers and 0 odd numbers, this can be done in

\dbinom 33 \dbinom 30 = 1\cdot1 = 1

way.

The total count is then the sum of all possible selections with at least 1 even number and between 0 and 3 odd numbers.

\displaystyle \sum_{e=1}^3 \binom 3e \sum_{o=0}^3 \binom 3o = 2^3 \sum_{e=1}^3 \binom3e = 8 \left(\sum_{e=0}^3 \binom3e - \binom30\right) = 8(2^3 - 1) = \boxed{56}

where we use the binomial identity

\displaystyle \sum_{k=0}^n \binom nk = \sum_{k=0}^n \binom nk 1^{n-k} 1^k = (1+1)^n = 2^n

3 0
1 year ago
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