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3 years ago

Could an average person lift the weight of $100 in dimes?

Mathematics

2 answers:

kolezko [41]3 years ago

6 0

Yes. it would be only about 5 pounds

VLD [36.1K]3 years ago

5 0

Yeah they can lift the weight of 100 dimes

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Please tell the answer and show the work.

LUCKY_DIMON [66]

First step, i would try to figure out the slope. think of it as a typical y=mx+b linear equation as you check out the graph.

it's just rise over run (rise up this many, run over that many), and your options are (-2/3) or (-3/2)

start at the y-intercept, which is just above the middle of the graph. if you go down 2 and try to go over 3, you hit the line before you can count 3 units. that means this slope is incorrect.

go back to the y-intercept. down 3, over 2--there you go. your slope here is (-3/2), which immediately gets rid of half your answer choices for having the wrong slope

the next thing you have to do is decide where this graph should be shaded. the shaded region shows the domain; the white region shows what's outside of your domain. this inequality is shaded "below" which means that the y values are LESS than "(-3/2)x +1"

that eliminates another one of your answer choices; choice 3 is correct. the inequality is y < (-3/2)x + 1

if the graphs of inequalities are shaded below and the line is dotted, it's less than. if the graphs of inequalities are shaded above and the line is dotted, it's greater than. general rules for ya

5 0

3 years ago

Read 2 more answers

Limit as x approaches 0 of csc3x/cotx

jolli1 [7]

Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.

For instance, we can find the lim by using the number -.00001 for x and solve
csc(3x) / cot(x)
csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3

We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3

So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3

 $\lim_{x\to 0} \frac{csc(3x)}{cot(x)} = \frac{1}{3}$

6 0

3 years ago

A work shift for an employee at a restaurant consist of 10 hours. What fraction of employees work shift is represented by 8 hour

svp [43]

Answer:

4/5

Step-by-step explanation:

10:100=8:x

x= 100*8/10

x= 80 (80%)

80% = 80/100 = 8/10 = 4/5

4 0

3 years ago

PLEASE HELP ME WITH THIS QUESTION ITS URGENT!!!

Alex Ar [27]

Start by distributing the exponent to each of the terms in $(2u)^{3}$ . This will become $2^{3} u^{3}$ , and $2^{3} =8$ . Now, the expression is:

$\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }$ .

We can now simplify the bottom to read: $8u^{5}$ because when multiplying variables raised to an exponent, we add the exponents. The expression now looks like:

$\frac{2u^{3} v^{2} }{8u^{5} }$

The 2/8 simplifies to 1/4:

$\frac{u^{3} v^{2} }{4u^{5} }$

Now, we have two u terms on the top and bottom. When dividing variables raised to an exponent, we subtract the exponents. However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent. The final answer is:

$\frac{v^{2} }{4u^{2} }$

Hope this makes sense!!

4 0

3 years ago

Find the cosine of ∠J.

RUDIKE [14]

Answer:

$\cos = \frac{base}{hypotenuse} = \\ \cos(j) = \frac{ \sqrt{29} }{ \sqrt{94} } = \sqrt{ \frac{29}{94} } \\ answer = \sqrt{ \frac{29}{94} }$

6 0

3 years ago

Could an average person lift the weight of​ $100 in​ dimes?

Could an average person lift the weight of $100 in dimes?