Write this percentage as a fraction in its simplest form. 96 % (pls)

If 1/2 cup of fruit cocktail contains 13g of sugar, then 1 1/4 cup of fruit cocktail contains how many grams of sugar?

Alexus [3.1K]

Answer : 32.5 g of sugar

Step-by-step explanation:

1 1/4 cup = (4+1)/4 = 5/4 cup

If 1/2 cup contains 13 g of sugar

Then 5/4 cup contains C g of sugar

C = 5/4 * 13g➗1/2 = 5*13*2g➗4 = 130g➗4 = 32.5 g of sugar

Answer : 32.5 g of sugar

<h2>Spymore</h2>

7 0

3 years ago

Fill in the blank spaces please.

Kisachek [45]

PART A

If 4 pounds = 10 dollars...

4/2 = 2

10/2 = 5

So for 2 pounds, it would cost $5.00

Now for the 1 pound one

4/1 = 4

10/4 = 2.5

For the 1 pound one, it would cost $2.50

PART B

We know that 4 pounds = 10 bucks

Since 1 is 1/10 of 10 (in the cost section), we have to apply this to the pounds section. 4/10 = 0.4. Therefore, $1 = 0.4lb

Now for the last blank...

Since $1 = 0.4, we multiply that by 9. 0.4 x $9 = 3.6lb

HOPE THIS HELPED

5 0

2 years ago

A retailer purchased a camera for rs.1560 and sold it at 5% loss find the loss amount

zzz [600]

Answer:

Loss is Rs. 78

Step-by-step explanation:

Solution:

Given,

Cost Price (CP)= Rs.1560
Loss Percent (L%) = 5%

Here,

L%= L/CP ×100%

or,. 5 =L/1560×100

or,. 5×1560/100 =L

or,. L= Rs.78

Therefore, Loss is Rs.78

3 0

2 years ago

A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i

garri49 [273]

Answer:

The degrees of freedom first given by:

$df=n-1=12-1=11$

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

$t_{\alpha}= 1.796$

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :

Null hypothesis: $\mu \leq 5$

Alternative hypothesis: $\mu > 5$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The degrees of freedom first given by:

$df=n-1=12-1=11$

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

$t_{\alpha}= 1.796$

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0

3 years ago

How do I subtract fractions

sesenic [268]

To perform the correct operation as to subtract numbers, make sure the denominators are the same, and then one can then subtract and remove a smaller number from the larger one.

This same method also holds true for adding fractions together as well.

Another way to subtract fractions is to convert them from fraction form to decimal form and then align the decimal points and subtract the values.

3 0

3 years ago