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Dmitry_Shevchenko [17]
3 years ago
6

Wyatt is working two summer jobs, making $8 per hour walking dogs and making $14 per hour tutoring. In a given week, he can work

a maximum of 13 total hours and must earn a minimum of $140. If
x represents the number of hours walking dogs and
y represents the number of hours tutoring, write and solve a system of inequalities graphically and determine one possible solution.
Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

he spends 7 hours walking a dog and 6 hours tutoring

Step-by-step explanation:

you multiple 8 by 7 and get 56

then multiple 14 by 6 and get 84

you add 6 and 7 together and get 13 hours

you add 56 and 84 together and get 140

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zalisa [80]
The answer is 35/2 (fraction)
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3 years ago
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Please Please Please help with this math problem
katovenus [111]
  1. The revenue as a function of x is equal to -x²/20 + 920x.
  2. The profit as a function of x is equal to -x²/20 + 840x - 6000.
  3. The value of x which maximizes profit is 8,400 and the maximum profit is $3,522,000.
  4. The price to be charged to maximize profit is $500.

<h3>How to express the revenue as a function of x?</h3>

Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.

Mathematically, the revenue can be calculated by using the following expression:

R(x) = x × P(x)

Revenue, R(x) = x(-1/20(x) + 920)

Revenue, R(x) = x(-x/20 + 920)

Revenue, R(x) = -x²/20 + 920x.

Expressing the profit as a function of x, we have:

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = -x²/20 + 920x - (80x + 6000)

P(x) = -x²/20 + 840x - 6000.

For the value of x which maximizes profit, we would differentiate the profit function with respect to x:

P(x) = -x²/20 + 840x - 6000

P'(x) = -x/10 + 840

x/10 = 840

x = 840 × 10

x = 8,400.

For the maximum profit, we have:

P(x) = -x²/20 + 840x - 6000

P(8400) = -(8400)²/20 + 840(8400) - 6000

P(8400) = -3,528,000 + 7,056,000 - 6000

P(8400) = $3,522,000.

Lastly, we would calculate the price to be charged in order to maximize profit is given by:

P(x) = -1/20(x) + 920

P(x) = -1/20(8400) + 920

P(x) = -420 + 920

P(x) = $500.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

3 0
2 years ago
You invest $5000 in an account at 5.5% per year simple interest. How much will you have in the account at the beginning of the 6
NeX [460]

Answer:

The amount in the account in the  beginning of the 6th year is $6375 .

Step-by-step explanation:

Formula

Simple\ interest = \frac{Principle\times Rate\ times Time}{100}

As given

You invest $5000 in an account at 5.5% per year simple interest.

Principle = $ 5000

Rate = 5.5 %

Time = 5 years

(As calculate amount in the account for beginning of 6th year.)

Putting all the values in the formula

Simple\ interest = \frac{5000\times 5.5\times 5}{100}

Simple\ interest = 50\times 5.5\times 5

Simple interest = $ 1375

Amount =  Principle + Simple interest

Putting values in the above formula

Amount =  $5000 + $1375

Amount = $ 6375

Therefore the amount in the account in the  beginning of the 6th year is $ 6375 .

8 0
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bulgar [2K]
You would need 48 fifty dollar bills to make up 2,400 and you would need 5 five dollar bills to make up the 25, so then you’d have your answer which is $2,425.
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Which would result in the largest amount of money?!
nignag [31]

Answer:

c 364

Step-by-step explanation:

this is the correct answer because the rest are lower answers

8 0
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