By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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Answer:
Subtract 11 from both sides
Step-by-step explanation:
Answer:
x=-5
Step-by-step explanation:
Combine like terms: 7x-11=-46
Add 11 to -46: -35
Divide: 7x/-35
ANSWER: x=-5
Answer:
55
Step-by-step explanation:
m angle A and m angle C are equal sine two of those sides are equal. You would do 3x + 40 = x +50
You subtract x, leaving it to be 2x + 40 = 50
Subtract the 40, leaving it be 2x = 10
Divide both sides by 2, which leaves x = 5
and then you would do 3(5) + 40, which is 55
Answer:
there isnt enough information to answer the question.
Step-by-step explanation:
