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4 years ago

How to find the maximum or minimum value of a quadratic function?

Mathematics

1 answer:

kipiarov [429]4 years ago

6 0

Answer:

Vertex form

Step-by-step explanation:

You convert to vertex form a(x - b)^2 + c . The coordinates of the maxm/minm will be (b, c).

For example find minimum value of x^2 + 5x - 6:-

x^2 + 5x - 6

= (x + 2.5)^2 - 6.25 - 6

= (x + 2.5)^2 - 12.25

The coordinates of minimumm will be (-2.5, -12.25) The values of the minimum of the function is -12.25

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Find missing side x trig quiz q.4

Sladkaya [172]

Answer:

Step-by-step explanation:

Sinፀ = opposite / hypotenuse

sinፀ = 12mm / 48mm

ፀ= Arcsin(12/48)

=16.7°

7 0

3 years ago

Please help!!!Water flows through a pipe at a rate of 620 gallons every 5.5 minutes. Express this rate of flow in cups per secon

cestrela7 [59]

Answer:

30 cups/second

Step-by-step explanation:

620 gallons = 9,920 cups

5.5 minutes = 330 seconds

9,920/330 = ~30

7 0

3 years ago

A taut clothesline extends between the points (–4.2, –6.4, 4.5) and (7.1, 2.2, 5.8), where the coordinates are in units of feet.

Citrus2011 [14]

Answer:

17.54 ft

Step-by-step explanation:

Moving along the line from (–4.2, –6.4, 4.5) to (7.1, 2.2, 5.8), x increases by 11.3, y by 8.6 and z by 10.3.

Applying the Pythagorean Theorem twice, we get

(length of clothesline) = √( 11.3² + 8.6² + 10.3²), or 17.54 ft.

7 0

3 years ago

What is the answear for 5xy+4y-z+3xy

Irina18 [472]

Answer:

8xy+4y-z

Step-by-step explanation:

Add values with the same variables; in this case xy

6 0

4 years ago

line t has an equation of y=1/9x-9. Line u includes the point (4,1) and is parallel to line t. What is the equation of line u?

horrorfan [7]

Answer:

The equation of line 'U' is;

y = $\frac{x}{9}$ + 5

Step-by-step explanation:

A line 'T' has an equation; y = $\frac{1}{9}$ x - 9

A line 'U' passes through point (4,1) and is parallel to the line 'T'

We are to find the equation of line 'U'.

The slopes of two parallel lines are equal.

The slope of line 'T' is $\frac{1}{9}$ and so the slope of line 'U' is $\frac{1}{9}$

Since line 'U' passes through point (4,1) , we choose another point (x,y) still on the line.

Slope = change in y ÷ change in x

$\frac{1}{9}$ = $\frac{y - 1}{x - 4}$

Cross-multiplying gives;

9y - 9 = x - 4

9y = x - 4 + 9

9y = x + 5

y = $\frac{1}{9} x$ + 5 (and this is the equation of line 'U')

8 0

3 years ago