The remainder when p(x) is divided by (x+2) is; -79.
<h3>What is the remainder when p(X) is divided by (X+1)?</h3>
Since one of it's factors is (x+1), it follows that P(-1) = 0.
Hence; 0 = (-1)³ -4(-1)² -a +20
a = 15.
Hence, the polynomial is; p(x)=x3−4x2+15x+20
The remainder when p(x) is divided by (x+2) is;
p(-2) = (-2)³ -4(-2)² + 15(-5) +20
p(-2) = -8 -16 -75 +20
p(-2) = -79.
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In number form that would be 3,167
p.s.may i have the brainliest answer?
Answer:
Probability that student has a good grade = 0.525
Step-by-step explanation:
Given
Chances of earning a good grade when assignments are done on time = 0.80
Chances of earning a good grade when assignments are finished during class or late = 0.30
Chances of earning a good grade when assignments are not done at all = 0.05
% of students who completed assignment on time = 0.50
% of students who completed assignment during class = 0.40
% of students who did not completed assignment at all = 0.10
Probability that student has a good grade
= (0.80 *0.50) + (0.30*0.40) + (0.05*0.10)
= 0.525
9x^3 +11x^2 +3x- 33 is prime.
Answer:
m<ABC=27°
m<DBC=56°
Step-by-step explanation:
(x+10)+(4x-12)=83
5x-2=83
5x=83+2
5x=85
x=17
m<ABC=(x+10)=(17+10)=27°
m<DBC=(4x-12)=(4*17-12)=56°