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3 years ago

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In a bakery, a bag of bread rolls cost x dollars. A loaf of multi-grain bread costs $2 more than a bag of bread rolls. Mr. Lopez

pays $50 for some multi-grain loaves of bread. Write the number of loaves of bread he buys in terms of x.

1 answer:

Vaselesa [24]3 years ago

6 0

Step-by-step explanation:

Cost of bag of bread rolls is x

Multigrain is (+2) more.

So (x+2)

Y can be the number of multigrain loves Mr. Lopez buys.

Answer: y=50/(x+2)

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Instructions: Match each equations with correct type of event.

Mazyrski [523]

The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

P(A)P(B|A) - Dependent event
P(A)+P(B) - Mutually exclusive events
P(A and B)/P(A) - Conditional events
P(A) . P(B) - Independent Events
P(A)+P(B) -P(A and B) - not Mutually exclusive events.

When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

P(A and B) = P(A) . P(B|A)

When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

$\mathrm{P(B|A)=\frac{P(A~and~B)}{P(A)}}$

Hence the correct match are -

$\mathrm{P(A)P(B|A)\rightarrow}$ Dependent event
$\mathrm{P(A)+P(B)}\rightarrow$ Mutually exclusive events
$\mathrm{\frac{P(A ~and ~B)}{P(A)}\rightarrow}$ Conditional events
$\mathrm{P(A) . P(B)\rightarrow}$ Independent Events
$\mathrm{P(A)+P(B) -P(A ~and ~B)\rightarrow}$ not Mutually exclusive events.

Learn more about Probability of Events here -

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What is the solution to the system that is created by the equation y=-x+6 and the graph shown below

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If you were to plot the function y=-x+6, both functions meet at the point (4,2)

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D=.5*a*t^2 - solving for a<img src="https://tex.z-dn.net/?f=d%3D.5%2Aa%2At%5E2" id="TexFormula1" title="d=.5*a*t^2" alt="d=.5*a*

Leviafan [203]

Answer:

$\displaystyle a=\frac{d}{.5*t^2}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$d=.5*a*t^2$

It's required to solve it for a.

Swap sides to have the letter on the left side:

$.5*a*t^2=d$

Divide by $.5*t^2$ :

$\mathbf{\displaystyle a=\frac{d}{.5*t^2}}$

7 0

3 years ago

Please help! i dont understand

kvv77 [185]

QUESTION 1

The given inequality is

$y\leq x-3$ and $y\geq -x-2$ .

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

$-2\leq 3-3$ and $-2\geq -3-2$ .

$-2\leq 0$ :True and $-2\geq -5$ :True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is

$y\:>\:-3x+3$ and $y\:>\: x+2$ .

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

$4\:>\:-3(1)+3$ and $4\:>\: 1+2$ .

$4\:>\:0$ :True and $4\:>\: 3$ :True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is

$y\leq 3x-6$ and $y\:>\: -4x+2$ .

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

$-2\leq 3(0)-6$ and $-2\:>\: -4(0)+2$ .

$-2\leq -6$ :False and $-2\:>\:2$ :False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is

$2x-y\:$ and $x+y\:>\:-1$ .

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

$2(0)-3\:$ and $0+3\:>\:-1$ .

$-3\:$ :True and $3\:>\:-1$ : True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is

$y\:>\:2x-3$ and $y\:$ .

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

$0\:>\:2(-3)-3$ and $0\:$ .

$0\:>\:-9$ ;True and $0\:$ :True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

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3 years ago