To prove that ΔAED ˜ ΔACB by SAS, Jose shows that StartFraction A E Over A C EndFraction = StartFraction A D Over A B EndFractio

Question

3 years ago

12

n.
Triangle A E D is shown. Line segment B C is drawn from side A D to A E to form triangle A C B.

Jose also has to state that

please help!!!!!!

2 answers:

Ira Lisetskai [31] · Answer 1 · 2022-03-24T01:12:37+03:00

5 0

Answer:

A on Edg.

Step-by-step explanation:

Took the Test

Veseljchak [2.6K] · Answer 2 · 2022-03-24T02:58:34+03:00

3 0

Answer:

<A is congruent to <A

Step-by-step explanation:

<A is in both triangle and it can be equal to itself because of the reflexive property.