PLSSS HELPP!!!REAALLY need it its'overdue
1 answer:
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Answer:
Part A:
( 1.8333, -0.08333)
Part B:
x = 2 or x = 5/3
Step-by-step explanation:
The quadratic equation
has been given.
Part A:
We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.
Setting the derivative to 0;
6x - 11 = 0
6x = 11
x = 11/6
The corresponding y value is determined by substituting x = 11/6 into the original equation;
y = 3(11/6)^2 - 11(11/6) + 10
y = -0.08333
The vertex is thus located at the point;
( 1.8333, -0.08333)
Find the attached
Part B:
We can use the quadratic formula to solve for x as follows;
The quadratic formula is given as,
From the quadratic equation given;
a = 3, b = -11, c = 10
We substitute these values into the above formula and simplify to determine the value of x;
Answer:
x = = 10.8
Step-by-step explanation:
Both problems are done the same way. I will do the first one and you do the second one. OK?
Move the radius x to make a right triangle. The 6 unit segment bisects the chord. So, the legs of the right triangle are 6 and 9
The use the Pythagorean theorem to find x, which is the hypotenuse of the right triangle. Now,
= 10.8
None of the answer choices are to the nearest tenth. So, I am confused about that.
In the second problem, the answer should be 11.2