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Verdich [7]
3 years ago
11

t=" \frac{x}{10.1} = 3.5" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
dsp733 years ago
5 0

Answer:

x=35.35

Step-by-step explanation:

If you multiply \frac{x}{10.1} .1 by 10.1 that will cancel out the 10.1s, then since you multiplies one side of the equation by something you have to multiply the other too.  So 3.5*10.1 = 35.35.  Then since the 10.1s canceled out this leaves us with x=35.35.  Let me know if you need any more help.  

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4
ohaa [14]

Answer:

55.8292 cm

Step-by-step explanation:

Circumference is diameter x pi.

7 x 3.14 = 21.98 inches

21.98 x 2.54 = 55.8292 cm

4 0
2 years ago
Help finding mean of data set A and data set B?
Slav-nsk [51]

Answer:

Mean of A: 5.5

Mean of B: 3

Step-by-step explanation:

Mean of A: (4 + 5 * 3 + 6 * 3 + 7) / 8 = 5.5

Mean of B: (2 * 3 + 3 * 3 + 4 * 3) / 9 = 3

3 0
3 years ago
Write a cube - b cube in factor form​
Leokris [45]

Answer:

(a-b) {a raise2+b raise 2 - ab}

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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KonstantinChe [14]

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Mark as brainliest plz.

8 0
3 years ago
Will mark the Brainliest !!!!! A team of 5 boys and 4 girls will be chosen from a group of 16 boys and 13 girls,
vfiekz [6]

Answer:

Step-by-step explanation:

The total number of permutations of boys and girls on the team are:

¹⁶P₅*¹³P₄

1.

Bob will be one of the fixed boys to be picked. Hence, actually 4 boys are to be picked from 15. The permutations of girls being picked remains the same.

Probability = Permutations with Bob as one of the boys / Total permutations

Probability = (¹⁵P₄*¹³P₄) / (¹⁶P₅*¹³P₄) = ¹⁵P₄ / ¹⁶P₅

Probability = \frac{15!}{(15-4)!}/\frac{16!}{(16-5)!} = 15! / 16! = 1/16

2.

Now, Bob is one of the fixed boys and Jane is one of the fixed girls. Hence, actually 4 boys are to be picked from 15 and 3 girls are to be picked from 12.

Probability = Permutations with bob as one of the boys and jane as one of the girls / Total permutations

Probability = (¹⁵P₄*¹²P₃) / (¹⁶P₅*¹³P₄) = (1/16)*(1/13) = 1/208

3.

Now, the probability that at least Jane or Bob will be picked has been asked. This probability is a combination of three probabilities:

Probability = (Probability that only Bob will be picked) + (Probability that only Jane will be picked) + (Probability that both will be picked)

Probability = 1/16 + 1/13 + 1/208 = 0.123

4.

Total teams possible = ¹⁶P₅*¹³P₄ = 8994585600 teams are possible

5 0
3 years ago
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