<span>X/2 = 4/16
This is where you would use cross-multiplication.
Multiply the x with 16 and the 2 with 4.
16x = 8
Now divide everything by 16.
x = 0.5</span>
Start by decomposing the number inside the root into primes
Then group the terms into cubes if possible
rewrite the root
![\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D%5Csqrt%5B3%5D%7B10%5Ccdot2%5E3%7D)
then cancel the terms that are cubes and bring them out of the root
![\sqrt[3]{80}=2\sqrt[3]{10}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D2%5Csqrt%5B3%5D%7B10%7D)
Substitute with y = 4 and z = -2
= 4^2*(-2)/4 + 10
= 16*(-2)/4 + 10
= -32/4 + 10
= -8 + 10
= 2
Hope This Helped! Good Luck!
I like to think of radicals (or square roots) just as x terms-
here, we have the equivalent (kind of) to x * 4x.
Since these are both x terms and 4x= x*x*x*x, we can simply write 5x.
Im not sure what your teacher is asking you to communicate, but most simply would like to see evidence that you understand the material rather than simply looking up the answer... (i mean without reading an explanation xD)
4√x= √x*√x*√x*√xso √x • 4√x =5√x
