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evablogger [386]
3 years ago
9

What is the differnce between union and intersection in math

Mathematics
1 answer:
ss7ja [257]3 years ago
8 0
Union includes everything whether in common or not while intersection only includes elements in common
You might be interested in
Jerry wants to gravel an area represented by a square with side lengths of 3/4ft. What is the area he needs to fill.
Pani-rosa [81]

Answer:

0.5625 ft^2

Step-by-step explanation:

area of square = side * side

A = s^2

A = (0.75 ft)^2 = (0.75 ft)(0.75 ft) = 0.5625 ft^2

7 0
2 years ago
A right rectangular prism has a square base, with sides that are each 2 meters in length. The height of the prism is 34 meters.
Novosadov [1.4K]

Answer:

136m

Step-by-step explanation:

The formula for the volume of a rectangular prism is V = L · W · H

We can take the given values and multiply them to find our answer.

L = 2

W = 2

H = 34

2x2x34 = 136

4 0
2 years ago
Ibuki factored 12x^7as (4x^3)(3x^4)
Marina86 [1]

Answer:

Both are correct.

Step-by-step explanation:

The key understanding here is that you can factor a monomial in many different ways!

To check if any of the factorizations is correct, we can multiply the factors and see if their product is really 12x^712x

7

12, x, start superscript, 7, end superscript.

Hint #22 / 4

\begin{aligned} (\blueD{4}\maroonD{x^3})(\blueD{3}\maroonD{x^4})&=(\blueD{4})(\blueD{3})(\maroonD{x^3})(\maroonD{x^4}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(4x

3

)(3x

4

)

​

 

=(4)(3)(x

3

)(x

4

)

=12x

7

​

So Ibuki is correct!

Hint #33 / 4

\begin{aligned} (\blueD{2}\maroonD{x^6})(\blueD{6}\maroonD{x})&=(\blueD{2})(\blueD{6})(\maroonD{x^6})(\maroonD{x}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(2x

6

)(6x)

​

 

=(2)(6)(x

6

)(x)

=12x

7

​

So Melodie is also correct!

Both Ibuki and Melodie are correct.

8 0
3 years ago
Subtract the rational expression 1/x^2-x-6 - x/x+2.
Aleksandr [31]

Answer:

Step-by-step explanation:

x² - x -6 = x²  + 2x - 3x - 3*2

            =x(x + 2) - 3(x + 2)

            = (x + 2 )(x - 3)

\frac{1}{x^{2}-x-6}+\frac{x}{x+2}=\frac{1}{(x +2 )(x - 3)}-\frac{x}{x + 2}\\

                      = \frac{1}{(x+2)(x-3)}-\frac{x(x-3)}{(x+2)(x-3)}\\\\=\frac{1-x(x-3)}{(x+2)(x-3)}\\\\=\frac{1-x^{2}+3x}{(x+2)(x-3)}\\\\

4 0
2 years ago
Which relationships describe angles 1 and 2?
lozanna [386]
Complementary angles
Adjacent angles

Correct
7 0
2 years ago
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