If you are wonder how many seat there are left there would be 44 seats unoccupied. 200-156=44
You need to isolate the "x" in both inequalities
5x + 7 ≤ -3 Subtract 7 on both sides
5x ≤ -10 Divide 5 on both sides
x ≤ -2
3x - 4 ≥ 11 Add 4 on both sides
3x ≥ 15 Divide 3 on both sides
x ≥ 5
This is your simplified inequalities:
5x + 7 ≤ -3 or 3x - 4 ≥ 11 ---------> x ≤ -2 or x ≥ 5 Your answer is A
1. use the equation y -y1 = m(x-x1)
2. (-6,-4) is x1,y1 and (4,-6) is x2,y2
3. y-(-4) = m(x-(-6)
m is the gradient, 10/10, which is 1. make two negatives into a positive.
4. y+4 = x+6
therefore the equation of the lines is y = x+2
substitute the points back into the equation to double check.
