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3 years ago

PLZ HELP ME I REALLY NEED IT

Mathematics

1 answer:

kenny6666 [7]3 years ago

4 0

r = 2 inches

total h of the cylinder = 6+6+6 = 18 inches

$SA = 2\pi {r}^{2} + 2\pi \: rh$

$= 2\pi \: r(r + h)$

$= 2 \times 3.14 \times 2(2 + 18)$

$= 2 \times 3.14 \times 2 \times 20$

$= 251.2square \: inches$

You might be interested in

Is -7 bigger than - 8

alina1380 [7]

Hey!

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Answer:

True

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Explanation:

The smaller the negative number the bigger it is.

-7 > -8

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Hope This Helped! Good Luck!

8 0

2 years ago

The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b

storchak [24]

Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so $\mu = 145, \sigma = 25$ .

The fastest 10% are to be given advanced training. What task times qualify individuals for such training?

This is the value of X when Z has a pvalue of 0.90.

Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when $Z = 1.285$ .

$Z = \frac{X - \mu}{\sigma}$

$1.285 = \frac{X - 145}{25}$

$X - 145 = 32.125$

$X = 177.125$

A task time of 177.125s qualify individuals for such training.

7 0

3 years ago

The measures of two supplementary angles are (2x – 8)° and (3x - 2)°. What is the measure of the

saw5 [17]

Answer:

68°

Step-by-step explanation:

Here,

Two supplementary angles are (2x – 8)° and (3x - 2)°.

As we know that the sum of two supplementary angles are 180°. So,

→ (2x – 8)° + (3x – 2)° = 180°

→ 2x° – 8° + 3x° – 2° = 180°

→ 5x° – 10° = 180°

→ 5x° = 180° + 10°

→ 5x° = 190°

→ x = 190° ÷ 5°

→ x = 38°

Supplementary angles are,

1st angle = (2x – 8)°

→ 2(38°) – 8

→ (76 – 8)°

→ 68°

2nd angle = (3x – 2)°

→ 3(38°) – 2

→ (114 – 2)°

→ 112°

Therefore, the measure of the smaller angle is 68°.

4 0

2 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

2 years ago

2/3*x+3/4=8 what is x

matrenka [14]

Answer: x=10 7/8

Step-by-step explanation:

Subtract 3/4 from both sides. Multiply both sides by 3. Divide both sides by 2 (basically just isolate x on one side of the equal sign).

7 0

2 years ago