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Inessa [10]
3 years ago
10

How do multiplication properties and division rules help you multiply and divide?

Mathematics
2 answers:
stira [4]3 years ago
5 0

The properties of multiplication and division are an easier way when making calculations.

Let's see an example for each one.

Mutiplication:

Suppose we are going to multiply:

2 * 89

It is easier to make the product using the distributive property:

2 * 89 = 2 * (80 + 9)\\2 * 89 = (2 * 80) + (2 * 9)\\2 * 89 = 160 + 18\\2 * 89 = 178

Division:

Suppose we have the following division:

\frac{2}{0}

By properties of the division, we know that this division is not defined.

Therefore, when we see a division between 0, we know that the answer is that it is not defined.

Answer:

The rules of multiplication and division help to divide and multiply in a faster way.

Nikolay [14]3 years ago
3 0
<span>Multiplication and division properties and rules help us multiply and divide simply because they guide these basic math operations in determining the proper outcome such as the product and quotient of the objective numbers. For example, take for instance the zero property of multiplication, it states that any digit that is multiplied by zero is zero. This simple property provides us an idea that when there is a scenario that we are given an equation that is 1 x 0, we can answer the equation immediately which is 0.   </span>



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Rectangles are similar figures, thus if scaled copies of each other then the ratios of corresponding sides must be equal

compare ratios of lengths and widths

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4 years ago
An expression is shown below:
PolarNik [594]
Notation
I imagine that the expression you are asked to work with is:
3 x^{3}y+15xy-9 x^{2} y-45y

When you use a keyboard it is customary to use "^" to denote an exponent is coming so you could have written: 3x^3y+15xy-9x^2y-45y just to be clear.

PART A
To factor out the GCF we are looking for the greatest factor among the terms. Looking at the coefficients (the numbers) the largest number they can all be divided by is 3 so we will pull out a 3. Notice also that each term has a y in it so we can pull out that.

This gives us: 3 x^{3}y+15xy-9 x^{2} y-45y=3y( x^{3}+5x-3 x^{2} -15)

To factor is to write as a product (something times something else). It undoes multiplication so in this case if you take what we got and multiplied it back you should get the expression we started with.

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