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Svetach [21]
4 years ago
9

If x = -6, which inequality is true?

Mathematics
1 answer:
igomit [66]4 years ago
8 0

Answer:

C. 1 - 2x > 13

Step-by-step explanation:

you just substitute

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The vertices of a quadrilateral in the coordinate plane are known. How can the perimeter of the figure be found?
AlekseyPX

Answer:

Use the distance formula to find the length of each side, and then add the lengths.

Step-by-step explanation:

We are given the vertices of a quadrilateral in the coordinate plane.

We have to find the perimeter of the figure.

For doing so, we have to find the length of all the sides of a quadrilateral

The length of a line segment joining points (x1,y1) and (x2,y2) is given by the distance formula:  \sqrt{(x2-x1)^2+(y2-y1)^2}

after finding length of all the sides, we add the length of each side to get the perimeter.

Hence, the correct option is:

Use the distance formula to find the length of each side, and then add the lengths.

5 0
4 years ago
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If cde is a straight angle, de bisects gdh, m gde = (8x-1), m edh = (6x-15), and m cdf= 43, find each measure.
Sergio [31]

Answer:

x = 7°

<GDH = 112°

<FDH = 192°

<FDE = 135°

Step-by-step explanation:

If DE bisects <GDH this means that <GDE = <EDH

Given <GDE = (8x+1)° and <EDH = (6x+15)° then;

8x+1 = 6x+15

8x-6x = 15-1

2x = 14

x = 7°

Since <GDH = <GDE + <EDH

<GDH = 8x-1+6x+15

<GDH = 14x+14

<GDH = 14(7)+14

<GDH = 98+14

<GDH = 112°

For <FDH,

Note that sum of angle on a straight line is 180°

<FDH = <FDG + <GDE + <EDH

<FDH = <FDG + <GDH

<FDG = 180-(43+8x+1)

<FDG = 180-44-8x = 136-8x

<FDH = 136-8x+112

<FDH = 248-8x

<FDH = 248-8(7)

<FDH = 248-56

<FDH = 192°

For <FDE;

<FDE = <FDG + <GDE

<FDE = 136-8x+8x-1

<FDE = 135°

7 0
3 years ago
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